SQLAlchemy表使用两个外键定义关系 [英] SQLAlchemy table defining relationship using two foreign keys
问题描述
我有两个表,Users和ChatSessions.ChatSessions具有两个字段user_id和friend_id,它们都是Users表的外键.
I have two tables, Users and ChatSessions. ChatSessions has two fields, user_id and friend_id, both foreign keys to the Users table.
user_id始终包含发起聊天会话的用户,friend_id是另一个用户.由于某个用户可以由他或他的朋友发起聊天会话,因此他可以在各种会话中将其id设置为user_id或friend_id.
user_id always contains the user that initiated the chat session, friend_id is the other user. As a certain user can have chat sessions initiated by him, or his friends, he can have his id either as user_id or as friend_id, in various sessions.
是否有可能在用户"表中定义一个关系,无论他的id是在user_id还是friend_id中,我都可以访问该用户的所有chat_sessions?像这样:
Is it possible to define a relationship in the Users table, where i have access to all the chat_sessions of that user, no matter whether his id is in user_id or friend_id? Something like this:
chat_sessions = db.relationship('chat_sessions',
primaryjoin="or_(User.id==ChatSession.user_id, User.id==ChatSession.friend_id)",
backref="user")
当我尝试向Users表提交条目时收到以下错误:
I receive the following error when I try to commit an entry to the Users table:
ERROR main.py:76 [10.0.2.2] Unhandled Exception [93e3f515-7dd6-4e8d-b096-8239313433f2]: relationship 'chat_sessions' expects a class or a mapper argument (received: <class 'sqlalchemy.sql.schema.Table'>)
模型:
class User(db.Model):
__tablename__ = 'users'
id = db.Column(db.Integer, primary_key=True)
email = db.Column(db.String(60), index=True, unique=True)
password = db.Column(db.String(255))
name = db.Column(db.String(100))
active = db.Column(db.Boolean(), nullable=False)
chat_sessions = db.relationship('chat_sessions',
primaryjoin="or_(User.id==ChatSession.user_id, User.id==ChatSession.friend_id)")
class ChatSession(db.Model):
__tablename__ = 'chat_sessions'
id = db.Column(db.Integer, primary_key=True)
user_id = db.Column(db.Integer, db.ForeignKey('users.id'))
friend_id = db.Column(db.Integer, db.ForeignKey('users.id'))
status = db.Column(db.String(50))
user = db.relationship('User', foreign_keys=[user_id])
friend = db.relationship('User', foreign_keys=[friend_id])
推荐答案
不看表代码很难确定,但是删除backref参数可能就足够了.
It's difficult to be certain without seeing the tables' code, but it might be sufficient to remove the backref argument.
这是一个纯SQLAlchemy实现,似乎可以实现您想要的功能:
Here's a pure SQLAlchemy implementation that seems to do what you want:
import sqlalchemy as sa
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy import orm
Base = declarative_base()
class User(Base):
__tablename__ = 'users'
id = sa.Column(sa.Integer, primary_key=True)
name = sa.Column(sa.String)
all_chats = orm.relationship('Chat',
primaryjoin="or_(User.id==Chat.user_id, User.id==Chat.friend_id)")
def __repr__(self):
return f'User(name={self.name})'
class Chat(Base):
__tablename__ = 'chats'
id = sa.Column(sa.Integer, primary_key=True)
user_id = sa.Column(sa.Integer, sa.ForeignKey('users.id'))
friend_id = sa.Column(sa.Integer, sa.ForeignKey('users.id'))
user = orm.relationship('User', foreign_keys=[user_id])
friend = orm.relationship('User', foreign_keys=[friend_id])
def __repr__(self):
return f'Chat(user={self.user.name}, friend={self.friend.name})'
engine = sa.create_engine('sqlite:///')
Base.metadata.create_all(bind=engine)
Session = orm.sessionmaker(bind=engine)
usernames = ['Alice', 'Bob', 'Carol']
session = Session()
users = [User(name=name) for name in usernames]
session.add_all(users)
session.flush()
a, b, c = users
session.add(Chat(user_id=a.id, friend_id=b.id))
session.add(Chat(user_id=a.id, friend_id=c.id))
session.add(Chat(user_id=c.id, friend_id=a.id))
session.commit()
session.close()
session = Session()
users = session.query(User)
for user in users:
for chat in user.all_chats:
print(user, chat)
print()
session.close()
这是输出:
User(name=Alice) Chat(user=Alice, friend=Bob)
User(name=Alice) Chat(user=Alice, friend=Carol)
User(name=Alice) Chat(user=Carol, friend=Alice)
User(name=Bob) Chat(user=Alice, friend=Bob)
User(name=Carol) Chat(user=Alice, friend=Carol)
User(name=Carol) Chat(user=Carol, friend=Alice)
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