Java原因:实际参数和形式参数列表的长度不同 [英] java reason: actual and formal argument lists differ in length

问题描述

我需要帮助为我的代码创建一个setter方法.我为我的两个字符串值都创建了两个setter方法，但是我(A)不知道它们的实现是否正确，并且B)不知道如何调用它们以便它们出现在屏幕上.本质上，我希望能够仅调用我的lion和hippo类，并让它们具有名称和大小，而不必通过在主函数中直接插入类似的代码来实现它们河马h =新河马(汤姆"，"42")

I need help creating a setter method for my code. I have created two setter methods for both of my string values, but I am A) not sure if they are implemented correct, and B) not sure how to call them so that they appear on the screen. Essentially I would like to be able to just call my lion and hippo classes and have them already have a name and a size, and not have to implement them inside my main function directly by inserting something like Hippo h = new Hippo("Tom", "42")

package game2;


public class Game2 {

    public static void main(String[] args) {
        //I am getting the error here, what I want to do is figure out how to 
        //get this to work and then declare a name and size for the animal
        Hippo h = new Hippo();
        Lion l = new Lion(); 
    }

}

---

package game2;

public abstract class Animal {
    private String name;
    private String Size; 

    public String getName() {
        return name; 
    }

    public String getSize() {
        return Size; 
    }

    public void setName(String name) {
        name = "Tom"; 
    }

    public void setSize(String name) {
        name = "42"; 
    }


    public Animal(String theName, String theSize) {
        name = theName; 
        Size = theSize; 
    }
 }

---

package game2;

public class Hippo extends Animal {

    public Hippo(String name, String Size) {
        super(name, Size);
    }
}

---

package game2;

public class Lion extends Animal{

    public Lion(String name, String Size) {
        super(name, Size);
    }
}    

推荐答案

请记住，当您自己实现构造函数时，您会重载默认的构造函数.因此，您需要传递两个参数.

Remember when implement constructor by your own, you are overload the default constructor. So you need to pass two arguments.

实例化时，您没有传递构造函数的参数:

You didnot pass the arguments for constructors when you instantiate:

Hippo h = new Hippo();
Lion l = new Lion(); 

因为您的类构造函数需要两个参数.

Because your class constructors expect two parameters.

public Hippo(String name, String Size) {
    super(name, Size);
}

并且:

public Lion(String name, String Size) {
    super(name, Size);
}

解决方案:

在实例化对象时，您都可以传递参数:

Either you can pass arguments when you instantiating objects:

Hippo h = new Hippo("name", "33");
Lion l = new Lion("name", "22"); 

或者您需要为此实现重载的构造函数.

Or you need to implement overloaded constructors for these.

阅读了解有关构造函数重载的更多信息..

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