警告:赋值使指针从整数开始而不进行强制转换 [英] warning:assignment makes pointer from integer without a cast

问题描述

这是一个很常见的问题，但是我没有得到答案，所以再问一次.

Its quite a common question but I have not got my answer so asking it again.

我将构造函数定义为:

struct f_lock{
              int x;
              struct f_lock *next;
     };

然后说我有一个功能:

struct f_lock *new_node()
{
   struct f_lock *new_f_lock;
   .....
   return new_f_lock;
}

我从另一个函数调用:

struct f_lock *new_f_lock;
new_f_lock = new_node(); //This line gives the error warning:assignment makes pointer from integer without a cast

很乐意寻求帮助谢谢

推荐答案

您是否还收到错误的隐式声明函数"new_node" ?因为在这种情况下，您可能忘记了在调用它的模块中声明 new_node .(如果没有收到该错误，请使用 -Wall 重新编译以打开更多警告.)

Did you also get the error implicit declaration of function ‘new_node’? Because in that case, you probably forgot to declare new_node in the module where you're calling it. (If you're not getting that error, recompile with -Wall to turn more warnings on.)

警告消息的解释:如果未正确声明 new_node ，则编译器将假定它返回 int ，这是一种默认的返回类型(对于历史记录原因).

Explanation of the warning message: if new_node has not been declared properly, the compiler will assume it returns int, which is a kind of default return type (for historical reasons).

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