Lua正则表达式(ASCII(0-127)字符) [英] Lua regex for ascii(0-127) characters

问题描述

我正在使用LUA并尝试替换某些输入字符串中的非ascii字符.
我使用了 [^ \ x00– \ x7F] 正则表达式，但收到以下错误:
格式错误(缺少]")我也使用了 [^ [:ascii:]] ，但是它不起作用.
我认为 [^ \ x00– \ x7F] 是正确的方法，但我可能缺少一些转义.
请帮忙！

I am using LUA and trying to replace non ascii characters in some input string.
I used the [^\x00–\x7F] regex but getting the following error:
malformed pattern (missing ']') Also I used [^[:ascii:]] but it is does not work.
I think that [^\x00–\x7F] is the right way but I am probably missing some escape.
Please help!

推荐答案

要替换非ASCII字符:

To replace non-ascii characters:

string.gsub(your_string, "[\128-\255]", what_they_should_be_replaced_with)

替代方式:

string.gsub(your_string, "[^%z\1-\127]", what_they_should_be_replaced_with)

对于UTF-8文本:

string.gsub(your_string, "[\192-\255][\128-\191]*", what_they_should_be_replaced_with)

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