SQL 错误语法 1064 [英] SQL error syntax 1064
本文介绍了SQL 错误语法 1064的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我一直试图修复一个语法错误,但我无法弄清楚.错误说明
I have a syntax error that I have been trying to fix but I can't figure it out. Error tells that there is a problem near
'SET result = CONCAT(result,charac); END IF; SET indexchar = indexchar+1;'
我正在尝试创建的完整功能:
Full function I am trying to create:
DELIMITER //
DROP FUNCTION IF EXISTS `alphabet`;
CREATE FUNCTION `alphabet` (serial_number CHAR, name VARCHAR(100)) RETURNS VARCHAR(50)
DETERMINISTIC
BEGIN
DECLARE result VARCHAR(40) DEFAULT '';
DECLARE stringalpha VARCHAR(50) DEFAULT 'abcdefghijklmnopqrstuvwxyz0123456789';
DECLARE indexchar int DEFAULT 1;
DECLARE charlength INT;
DECLARE charac CHAR(1);
SET charlength = CHAR_LENGTH(stringalpha);
WHILE indexchar <= charlength DO
SET charac = SUBSTRING(stringalpha,indexchar,1);
IF (serial_number LIKE CONCAT('%',charac,'%') OR name LIKE CONCAT('%',charac,'%'))
SET result = CONCAT(result,charac);
END IF;
SET indexchar = indexchar+1;
END WHILE
RETURN result;
END //
DELIMITER ;
我尝试写没有成功:
SET result = CONCAT('result','charac');
推荐答案
DROP FUNCTION IF EXISTS `alphabet`;
DELIMITER //
CREATE FUNCTION `alphabet` (serial_number CHAR, name VARCHAR(100)) RETURNS VARCHAR(50)
DETERMINISTIC
BEGIN
DECLARE result VARCHAR(40) DEFAULT '';
DECLARE stringalpha VARCHAR(50) DEFAULT 'abcdefghijklmnopqrstuvwxyz0123456789';
DECLARE indexchar int DEFAULT 1;
DECLARE charlength INT;
DECLARE charac CHAR(1);
SET charlength = CHAR_LENGTH(stringalpha);
WHILE indexchar <= charlength DO
SET charac = SUBSTRING(stringalpha,indexchar,1);
IF (serial_number LIKE CONCAT('%',charac,'%') OR name LIKE CONCAT('%',charac,'%')) THEN
SET result = CONCAT(result,charac);
END IF;
SET indexchar = indexchar+1;
END WHILE; -- ********************** missing semi
RETURN result;
END //
DELIMITER ;
缺少THEN
,END WHILE
后缺少分号,顶部的分隔符在错误的行上
missing THEN
, missing semi-colon after END WHILE
, delimiter at the top was on the wrong line
这篇关于SQL 错误语法 1064的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文