不考虑时间对 NSDate 进行排序 - 只是日期 [英] Sort NSDate without respect to the time of day - just the date

问题描述

我有一个带有 nextCheck (NSDate)、lastName (NSString) 和 firstName (NSString) 键的数组控制器.我已经为数组设置了排序描述符.正如你在下面看到的，我首先按 nextCheck 排序，然后是 lastName，然后是 firstName.这似乎不起作用，因为 NSDate 不仅由日期组件组成，还由时间组件组成.有没有一种简单的方法可以只按日期组件排序?

I have an array controller with keys of nextCheck (NSDate), lastName (NSString), and firstName (NSString). I have set the sort descriptors for the array. As you can see below, I am sorting by nextCheck first, then lastName, then firstName. This appears to not be working because the NSDate is made up of not only a date component but also a time component. Is there an easy way to sort by the date component only?

[_arrayCurrentVisits setSortDescriptors:[NSArray arrayWithObjects:[NSSortDescriptor sortDescriptorWithKey:@"nextVisit" ascending:YES selector:@selector(compare:)],[NSSortDescriptor sortDescriptorWithKey:@"lastName" ascending:YES selector:@selector(localizedCaseInsensitiveCompare:)], [NSSortDescriptor sortDescriptorWithKey:@"firstName" ascending:YES selector:@selector(localizedCaseInsensitiveCompare:)], nil]];

推荐答案

最简单的解决方案是 添加一个名为 nextVisitDate 的方法，将截断"的 nextVisit 的值返回到午夜，然后排序nextVisitDate 代替.

The simplest solution would be to add a method called nextVisitDate returning the value of nextVisit "truncated" to midnight, and sort on nextVisitDate instead.

[_arrayCurrentVisits setSortDescriptors:[ //                           vvv HERE vvv
    NSArray arrayWithObjects:[NSSortDescriptor sortDescriptorWithKey:@"nextVisitDate"  ascending:YES selector:@selector(compare:)]
,   [NSSortDescriptor sortDescriptorWithKey:@"lastName" ascending:YES selector:@selector(localizedCaseInsensitiveCompare:)]
,   [NSSortDescriptor sortDescriptorWithKey:@"firstName" ascending:YES selector:@selector(localizedCaseInsensitiveCompare:)]
,   nil]];

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