如何在没有 NullPointerException 的情况下返回数组对象? [英] How to return an array object without NullPointerException?
本文介绍了如何在没有 NullPointerException 的情况下返回数组对象?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
声明:
private Man[] man;
这是初始化:
Man[] man = new Man[1];
for (int i = 0; i < 1; i++){
man[i] = new Man();
for (int j = 0; j < 3; j++){
man[i].eatThis(table.foods[table.topFood-1]);
table.topFood--;
}
}
想打印这个:
System.out.println(getMan(0));
转到:
public Man getMan(int k){
return man[k];
}
但我收到 NullPointerException.为什么?同时:
but I receive NullPointerException. Why? While:
System.out.println(man[0]);
工作正常.
Exception in thread "main" java.lang.NullPointerException
at ManRunning.getMan(ManRunning.java:80)
at ManRunning.newGame(ManRunning.java:133)
at ManRunning.<init>(ManRunning.java:57)
at RunDevilRun.main(RunDevilRun.java:9)
推荐答案
行(1)
Man[] man = new Man[1];
隐藏在这行(2)中声明的实例变量
is hiding the instance variable declared in this line (2)
private Man[] man;
任何体面的 IDE 都会对此显示警告.
any decent IDE would show a warning for this.
这里是你应该如何初始化第 (1) 行中用第 (2) 行声明的数组 man
here is how you should initialize the array man in the line (1) declared with line (2)
man = new Man[1];
这篇关于如何在没有 NullPointerException 的情况下返回数组对象?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文