重命名重复的索引值 pandas DataFrame [英] Rename duplicated index values pandas DataFrame
本文介绍了重命名重复的索引值 pandas DataFrame的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个包含一些重复索引值的 DataFrame:
I have a DataFrame that contains some duplicated index values:
df1 = pd.DataFrame( np.random.randn(6,6), columns = pd.date_range('1/1/2010', periods=6), index = {"A", "B", "C", "D", "E", "F"})
df1.rename(index = {"C": "A", "B": "E"}, inplace = 1)
ipdb> df1
2010-01-01 2010-01-02 2010-01-03 2010-01-04 2010-01-05 2010-01-06
A -1.163883 0.593760 2.323342 -0.928527 0.058336 -0.209101
A -0.593566 -0.894161 -0.789849 1.452725 0.821477 -0.738937
E -0.670305 -1.788403 0.134790 -0.270894 0.672948 1.149089
F 1.707686 0.323213 0.048503 1.168898 0.002662 -1.988825
D 0.403028 -0.879873 -1.809991 -1.817214 -0.012758 0.283450
E -0.224405 -1.803301 0.582946 0.338941 0.798908 0.714560
我只想更改重复值的名称并获得如下所示的 DataFrame:
I would like to change only the name of the duplicated values and to obtain a DataFrame like the following one:
ipdb> df1
2010-01-01 2010-01-02 2010-01-03 2010-01-04 2010-01-05 2010-01-06
A -1.163883 0.593760 2.323342 -0.928527 0.058336 -0.209101
A_dp -0.593566 -0.894161 -0.789849 1.452725 0.821477 -0.738937
E -0.670305 -1.788403 0.134790 -0.270894 0.672948 1.149089
F 1.707686 0.323213 0.048503 1.168898 0.002662 -1.988825
D 0.403028 -0.879873 -1.809991 -1.817214 -0.012758 0.283450
E_dp -0.224405 -1.803301 0.582946 0.338941 0.798908 0.714560
我的方法:
(i) 用新名字创建字典
(i) Create dictionary with new names
old_names = df1[df1.index.duplicated()].index.values
new_names = df1[df1.index.duplicated()].index.values + "_dp"
dictionary = dict(zip(old_names, new_names))
(ii) 仅重命名重复的值
(ii) Rename only the duplicated values
df1.loc[df1.index.duplicated(),:].rename(index = dictionary, inplace = True)
但是这似乎不起作用.
推荐答案
您可以使用 Index.where
:
You can use Index.where
:
df1.index = df1.index.where(~df1.index.duplicated(), df1.index + '_dp')
print (df1)
2010-01-01 2010-01-02 2010-01-03 2010-01-04 2010-01-05 2010-01-06
A -1.163883 0.593760 2.323342 -0.928527 0.058336 -0.209101
A_dp -0.593566 -0.894161 -0.789849 1.452725 0.821477 -0.738937
E -0.670305 -1.788403 0.134790 -0.270894 0.672948 1.149089
F 1.707686 0.323213 0.048503 1.168898 0.002662 -1.988825
D 0.403028 -0.879873 -1.809991 -1.817214 -0.012758 0.283450
E_dp -0.224405 -1.803301 0.582946 0.338941 0.798908 0.714560
如果需要删除重复的索引到唯一:
And if need remove of duplicated index to unique:
print (df1)
2010-01-01 2010-01-02 2010-01-03 2010-01-04 2010-01-05 2010-01-06
A -1.163883 0.593760 2.323342 -0.928527 0.058336 -0.209101
A -0.593566 -0.894161 -0.789849 1.452725 0.821477 -0.738937
E -0.670305 -1.788403 0.134790 -0.270894 0.672948 1.149089
E -0.670305 -1.788403 0.134790 -0.270894 0.672948 1.149089
E -0.670305 -1.788403 0.134790 -0.270894 0.672948 1.149089
F 1.707686 0.323213 0.048503 1.168898 0.002662 -1.988825
D 0.403028 -0.879873 -1.809991 -1.817214 -0.012758 0.283450
E -0.224405 -1.803301 0.582946 0.338941 0.798908 0.714560
df1.index = df1.index + df1.groupby(level=0).cumcount().astype(str).replace('0','')
print (df1)
2010-01-01 2010-01-02 2010-01-03 2010-01-04 2010-01-05 2010-01-06
A -1.163883 0.593760 2.323342 -0.928527 0.058336 -0.209101
A1 -0.593566 -0.894161 -0.789849 1.452725 0.821477 -0.738937
E -0.670305 -1.788403 0.134790 -0.270894 0.672948 1.149089
E1 -0.670305 -1.788403 0.134790 -0.270894 0.672948 1.149089
E2 -0.670305 -1.788403 0.134790 -0.270894 0.672948 1.149089
F 1.707686 0.323213 0.048503 1.168898 0.002662 -1.988825
D 0.403028 -0.879873 -1.809991 -1.817214 -0.012758 0.283450
E3 -0.224405 -1.803301 0.582946 0.338941 0.798908 0.714560
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