解析特定格式的字符串 [英] Parse a string in a particular format

问题描述

我有一个如下所示的响应字符串，我需要解析它并将其存储在我的类中.格式如下:

I have a response String as shown below which I need to parse it and store it my class. Format is shown below:

• 任务名称后跟这条虚线------------- 也是固定的
• 然后就在 key:value 对下方.它可以有多个键值对

• task name followed by this dotted line ------------- which is also fixed
• and then just below key:value pair. It can have many key value pair

下面是响应字符串.

abc-------------
Load:79008
Peak:4932152

def-------------
Load:79008
Peak:4932216

ghi-------------
Load:79008
Peak:4874588

pqr-------------
Load:79008
Peak:4874748

下面是我的课:

public class NameMetrics {

    private String name;
    private Map<String, String> metrics;

    // setters and getters

}

在上面的类中，name 应该是 abc 并且 metrics 地图应该有 Load 作为键和79008 作为值，与其他键值对相同​​.我想使用正则表达式，但不确定是否可以在这里使用正则表达式.

In the above class, name should be abc and metrics map should have Load as the key and 79008 as the value and same with other key:value pairs. I was thinking to use regex but not sure whether I can use regex here.

private static final Pattern PATTERN = Pattern.compile("(\\S+):\\s*(\\S*)(?:\\b(?!:)|$)");

String response = restTemplate.getForObject(url, String.class);
// here response will have above string.

最好的方法是什么?

推荐答案

BufferedReader reader = new BufferedReader(...???...);
NameMetrics current = null;
List<NameMetrics> result = new ArrayList<>();
while (true) {
  String s = reader.readLine();
  if (s == null) {
    break;  // end reached
  }
  if (s.trim().isEmpty()) {
    continue;  // Skip empty line
  }
  int cut = s.indexOf(':');
  if (cut == -1) {
    cut = s.indexOf('-');
    if (cut == -1) {
      continue;
    }
    current = new NameMetrics();
    current.setName(s.substring(0, cut));
    result.add(current);
  } else if (current != null) {
    current.setMetrics(s.substring(0, cut), s.substring(cut+1));
  }
}

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