PowerShell 是否要求脚本块的左花括号在同一行上? [英] Does PowerShell require the opening curly brace of a script block to be on the same line?

问题描述

好的，这个脚本的预期输出"是相当明显的，它可以工作.它复制文件:

Okay, the expected "output" of this script is fairly obvious, and it works. It copies files:

Get-ChildItem -Recurse -Directory | ForEach-Object{
    if ($_.Name.ToUpper().Contains("INCLUDE_PUBLIC")){
        Get-ChildItem -Recurse -File -Include "*.h" -Path $_.FullName | ForEach-Object {Copy-Item ($_.FullName) ("e:\IncTest")}
    }
}

但是，如果我将左大括号 { 移动到下一行，我会得到以下输出:

However, if I move the opening brace { to the next line, I get the following output:

cmdlet ForEach-Object at command pipeline position 2
Supply values for the following parameters:
Process[0]: 

我是否被其他一些语法问题欺骗了，或者 ForEach-Object 是否要求它的大括号在同一行上?

Am I getting tricked by some other syntax issue, or does ForEach-Object require its brace to be on the same line?

推荐答案

PS C:\> Get-Help -Name 'ForEach-Object'

SYNTAX
    ForEach-Object [-MemberName] <String> [-ArgumentList <Object[]>] [-Confirm] [-InputObject <PSObject>] [-WhatIf] [<CommonParameters>]

    ForEach-Object [-Process] <ScriptBlock[]> [-Begin <ScriptBlock>] [-Confirm] [-End <ScriptBlock>] [-InputObject <PSObject>] [-RemainingScripts <ScriptBlock[]>] [-WhatIf] [<CommonParameters>]

通过使用脚本块，您将使用 ForEach-Object cmdlet 的位置绑定参数.在这种情况下，-Process { } 参数集.如果您转义行尾(本质上，转义换行符)，您可以绕过该问题，但这通常是一种不好的做法.

By using a script block, you're using positionally-bound parameters of the ForEach-Object cmdlet. In this case, the -Process { } parameter set. If you escape the end of the line (in essence, escaping the newline), you can get around that, but it's generally a bad practice.

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