pyqt 和 websocket 客户端.在后台监听 websocket [英] pyqt and websocket client. listen websocket in background

问题描述

我有一个 PyQt Gui 应用程序.此应用程序有一个主窗口，应在启动后打开.

I have a PyQt Gui application. This application have a main window that should be open after the start.

这个应用程序应该监听 websocket.

This application should to listen the websocket.

我尝试解决它:

...

if __name__ == '__main__':
    app = QtGui.QApplication(sys.argv)

    window = Window()
    window.show()

    websocket.enableTrace(True)
    ws = websocket.WebSocketApp("ws://localhost:8080/chatsocket",
                                on_message = on_message,
                                on_error = on_error,
                                on_close = on_close)
#    ws.on_open = on_open

    ws.run_forever()

    sys.exit(app.exec_())

但是，启动应用程序后，主窗口没有打开.

But, after start application the main window was not open.

没有ws.run_forever()"行，主窗口打开，但应用程序不监听 websocket.

Without line "ws.run_forever()" the main window was open but application does not listen websocket.

我需要在后台"监听 websocket?你能帮我吗?

I need listen the websocket in the "background"? Can you help me?

PS:(对不起我的英语)

PS: (Sorry for my english)

推荐答案

感谢 enginefree.

Thanks enginefree.

我做这个

class Window(QtGui.QDialog):
    def __init__(self, parent=None):
        super(Window, self).__init__()

        self.thread = ListenWebsocket()
        self.thread.start()

...


class ListenWebsocket(QtCore.QThread):
    def __init__(self, parent=None):
        super(ListenWebsocket, self).__init__(parent)

        websocket.enableTrace(True)

        self.WS = websocket.WebSocketApp("ws://localhost:8080/chatsocket",
                                on_message = self.on_message,
                                on_error = self.on_error,
                                on_close = self.on_close) 

    def run(self):
        #ws.on_open = on_open

        self.WS.run_forever()


    def on_message(self, ws, message):
        print message

    def on_error(self, ws, error):
        print error

    def on_close(self, ws):
        print "### closed ###"

if __name__ == '__main__':
    app = QtGui.QApplication(sys.argv)

    QtGui.QApplication.setQuitOnLastWindowClosed(False)

    window = Window()
    window.show()

    sys.exit(app.exec_())

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