使用python的字计数器 [英] Word counter using python

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本文介绍了使用python的字计数器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我用python写了一个字数统计代码.

I wrote a code for word count in python.

我想从以下页面获取每个单词的文本和频率:http://www.holybible.or.kr/B_NIV/cgi/bibleftxt.php?VR=NIV&VL=1&CN=1&CV=99

I wanted to get text and frequency of each words from the following page: http://www.holybible.or.kr/B_NIV/cgi/bibleftxt.php?VR=NIV&VL=1&CN=1&CV=99

问题是我的程序给了我除以每节经文的字数,但我希望它不分开.

Problem is that my program is giving me the word count divided by each verses, but I want it undivided.

请帮我解决这个问题.

import requests
from bs4 import BeautifulSoup
import operator


def start(url):
    word_list = []
    source_code = requests.get(url).text  
    soup = BeautifulSoup(source_code, "html.parser")
    for bible_text in soup.findAll('font', {'class': 'tk4l'}):
        content = bible_text.get_text()   
        words = content.lower().split() 
        for each_word in words:
            word_list.append(each_word)
        clean_up_list(word_list)


def clean_up_list(word_list):
    clean_word_list = []
    for word in word_list:                                  
        symbols = "~!@#$%^&*()_+`{}|\"?><`-=\][';/.,']"
        for i in range(0, len(symbols)):
            word = word.replace(symbols[i], "")               
        if len(word) > 0:     
            clean_word_list.append(word)
    create_dictionary(clean_word_list)


def create_dictionary(clean_word_list):
    word_count = {}
    for word in clean_word_list:
        if word in word_count:
            word_count[word] += 1
        else:
            word_count[word] = 1  
    for key, value in sorted(word_count.items(),key=operator.itemgetter(0)):
        print(key, value)                  


start('http://www.holybible.or.kr/B_NIV/cgi/bibleftxt.php?VR=NIV&VL=1&CN=1&CV=99')

<小时>

推荐答案

您正在为每节经文构建一个新的 word_count 字典,然后打印出 word_count 仅用于这节经文.相反,您只需要一个 word_count 实例.

You are building a fresh word_count dictionary for every verse and then you printing out the word_count for only this verse. Instead you need to have only one instance of word_count.

更新:代码存在其他问题,此外您应该使用正则表达式删除所有非字母数字字符,此外您应该使用 collections.Counter,如它使您的代码更短,并且作为一个很好的副作用,让您检索最常用的单词:

Update: There were other problems with the code, plus you should use regular expressions to remove all non-alphanumeric characters, plus you should use collections.Counter, as it makes your code a lot shorter, and, as a nice side effect, let's you retrieve the most common words:

import requests
import re
from bs4 import BeautifulSoup
from collections import Counter


def parse(url):
    html = requests.get(url).text
    soup = BeautifulSoup(html, "html.parser")
    count = Counter()
    for bible_text in soup.findAll('font', {'class': 'tk4l'}):
        text = re.sub("[^\w0-9 ]", "", bible_text.get_text().lower())
        count.update(text.split(" "))
    return count

word_count = parse('http://www.holybible.or.kr/B_NIV/cgi/bibleftxt.php?VR=NIV&VL=1&CN=1&CV=99')
print(word_count.most_common(10))

输出:

[('the', 83), ('and', 71), ('god', 30), ('was', 29), ('to', 22), ('it', 17), ('of', 16), ('there', 16), ('that', 15), ('in', 15)]

这篇关于使用python的字计数器的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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