Python3.3 四舍五入 [英] Python3.3 rounding up

问题描述

在 Python 中，我想将两个数字相除，如果答案不是整数，我希望将数字四舍五入为上面的数字.
例如 100/30 不是给出 33.3，而是给出 4.谁能建议如何做到这一点?谢谢.

In Python I would like to divide two numbers and if the answer is not an integer I want the number to be rounded up to the number above.
For example 100/30 not to give 33.3 but to give 4. Can anyone suggest how to do this? Thanks.

推荐答案

你可以使用python自带的数学库中的ceil函数，也可以从逻辑上看看为什么

you can use the ceil function in math library that python has, but also you can take a look why in a logical sense

a = int(100/3) # this will round down to 3
b = 100/3 # b = 33.333333333333336, a and b are not equal

so we can generalize into the following

def ceil(a, b):
    if (b == 0):
        raise Exception("Division By Zero Error!!") # throw an division by zero error
    if int(a/b) != a/b:
        return int(a/b) + 1
    return int(a/b)

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