触摸图标时如何显示弹出菜单 [英] how to show popup menu when touching in Icon

问题描述

https://cmichel.io/how-to-create-a-more-popup-menu-in-react-native/我需要如何从这个例子中调用 popupmenu

https://cmichel.io/how-to-create-a-more-popup-menu-in-react-native/ how I need to call popupmenu from this example

推荐答案

假设你的模块中有 UIManagerModule.showPopupMenu，然后你可以通过UIManager class

Assuming that you have UIManagerModule.showPopupMenu in your modules, then you can call this class via UIManager class

import { UIManager, findNodeHandle } from 'react-native'

UIManager.showPopupMenu(
    findNodeHandle(this.state.icon),
    this.props.actions,
    this.onError,
    this.props.onPress
  )

通过找到icon的reference node打开，如图此处.

It is opened by finding the reference node of the icon as shown here.

它仅适用于 android，但可以遵循 这里

It works only on android though, and can be followed here

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