查找两个子字符串之间的所有字符串 [英] Find all strings that are in between two sub strings

问题描述

我以以下字符串为例:

string = "@@cat $$ @@dog$^"

我想提取所有锁定在@@"和$"之间的字符串，所以输出将是:

["cat","dog"]

我只知道如何提取第一次出现:

导入重新r = re.compile('@@(.*?)$')m = r.search(字符串)如果米:result_str = m.group(1)

想法和想法欢迎就如何捕获它们提出建议.

解决方案

使用 re.findall() 获取子字符串的每次出现.$ 被认为是正则表达式中的一个特殊字符，意思是 —字符串的结尾"锚点，因此您需要转义 $ 以匹配文字字符.

<预><代码>>>>进口重新>>>s = '@@cat $$ @@dog$^'>>>re.findall(r'@@(.*?)\$', s)[' 猫狗']

要删除前导和尾随空格，您只需将其匹配到捕获组之外即可.

<预><代码>>>>re.findall(r'@@\s*(.*?)\s*\$', s)['猫狗']

此外，如果上下文有可能跨越换行符，您可以考虑使用否定.

<预><代码>>>>re.findall(r'@@\s*([^$]*)\s*\$', s)

I have the following string as an example:

string = "@@ cat $$ @@dog$^"

I want to extract all the stringa that are locked between "@@" and "$", so the output will be:

[" cat ","dog"]

I only know how to extract the first occurrence:

import re
r = re.compile('@@(.*?)$')
m = r.search(string)
if m:
   result_str = m.group(1) 

Thoughts & suggestions on how to catch them all are welcomed.

解决方案

Use re.findall() to get every occurrence of your substring. $ is considered a special character in regular expressions meaning — "the end of the string" anchor, so you need to escape $ to match a literal character.

>>> import re
>>> s = '@@ cat $$ @@dog$^'
>>> re.findall(r'@@(.*?)\$', s)
[' cat ', 'dog']

To remove the leading and trailing whitespace, you can simply match it outside of the capture group.

>>> re.findall(r'@@\s*(.*?)\s*\$', s)
['cat', 'dog']

Also, if the context has a possibility of spanning across newlines, you may consider using negation.

>>> re.findall(r'@@\s*([^$]*)\s*\$', s)

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