编译器能否正确处理静态变量的初始化顺序? [英] Can the compiler deal with the initialization order of static variables correctly?

问题描述

以下情况如何?如果存在依赖，编译器能否正确处理静态变量的初始化顺序?

How about the following case? Can the compiler deal with the initialization order of static variables correctly if there is dependency?

a.h

template<class T>
struct A { static double a; };

template<class T>
double A<T>::a = 1;

b.h

struct B { static double b; };

b.cpp

#include "b.h"
#include "a.h"

double B::b = A<int>::a;

推荐答案

在您的示例中，A<int>::a 是静态初始化的，并且所有静态初始化都发生在任何动态初始化之前.B::b 是动态初始化的，所以它会在 A::a 初始化后发生，一切正常.

In your example, A<int>::a is initialized statically, and all static initialization takes place before any dynamic initialization. B::b is initialized dynamically and so it will happen after A<int>::a is initialized, and everything is fine.

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