名称查找紧跟在限定的 declarator-id 之后 [英] The name lookup followed after qualified declarator-id

问题描述

我试图理解以下引用的含义 (3.4.3/3 N3797):

I'm trying to understand what does the following quote mean (3.4.3/3 N3797):

在qualified-id之后的名称在范围内查找成员的类或命名空间.

names following the qualified-id are looked up in the scope of the member’s class or namespace.

namespace A
{
    class C
    {
    public:
        static const int a=7;
        static int b;
    };
}

int A::C::b=a; //7

static int b; 的作用域仅由 b 的声明点后面的声明区域组成.其实:

The scope of the static int b; consist only of the declarative region following by the b's point of declaration. Actually:

在类中声明的名称的潜在范围不仅包括名称声明点之后的声明区域，但是也包括所有函数体、默认参数、异常规范和大括号或相等的初始值设定项该类中的非静态数据成员

The potential scope of a name declared in a class consists not only of the declarative region following the name’s point of declaration, but also of all function bodies, default arguments, exception-specifications, and brace-or-equal-initializers of non-static data members in that class

这意味着static const int a=7;不属于static int b;的范围.因此，在 int A::C::b=a; 中找不到 static const int a=7.

This implies that static const int a=7; does not belong to the scope of static int b;. Hence the static const int a=7 cannot be found in the int A::C::b=a;.

这是标准中的错字还是我的误解?

It is a typo in the Standard or it is my misunderstanding?

推荐答案

这意味着 static const int a=7;不属于范围静态 int b;.因此静态 const int a=7 不能在int A::C::b=a;.

This implies that static const int a=7; does not belong to the scope of static int b;. Hence the static const int a=7 cannot be found in the int A::C::b=a;.

没有.它准确地暗示了您可以在那里阅读的内容:在类中声明的名称的潜在范围还 包含非静态数据成员的函数体等.这与上面的引用并不冲突 - 静态数据成员的声明区域(和范围)仍然包含它本身声明的类的范围.

No. It implies exactly what you can read there: The potential scope of a name declared in a class also contains function bodies etc. of non-static data members. That does not conflict with the quote above that - the declarative region (and the scope) of a static data member still contains the scope of the class it was declared in itself.

您自己引用了相关部分:

You quoted the relevant part yourself:

在qualified-id之后的名称在范围内查找成员的类或命名空间

names following the qualified-id are looked up in the scope of the member’s class or namespace

因此，由于在此代码片段中

Therefore, since in this code-snippet

int A::C::b=a;

a 用在 declarator-id 之后，在类中查找并找到.

a is used after the declarator-id, it is looked up in the class and found.

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