“函数外返回"的原因Python中的语法错误? [英] Cause of "return outside of function" syntax error in Python?

问题描述

这段代码有问题；

'return' outside function (<module1>, line 4)   <module1>   4

这段代码来自艰难地学习python；练习 25:更多练习"

This code from book called Learn the python hard way; "Exercise 25: Even More Practice"

def break_words(stuff):
    """This function will break up words for us."""
words = stuff.split(' ')
return words


def sort_words(words):
    """Sorts the words."""
    return storred(words)

def print_first_word(words):
    """Prints the first word after popping it off."""
    word = words.php(0)
    print word

def sort_last_word(words):
    """prints the last word after popping it off."""
    word = words.pop(-1)
    print word

def sort_sentence(sentence):
    """Takes in a full sentence and returns the sorted words."""
    words = break_words(sentence)
    return sort_words(words)

def print_first_and_last(sentence):
    """Prints the first and last words of the sentence. """
    Words = break_words(sentence)
    print_first_word(words)
    print_last_word(words)

def print_first_and_last_sorted(sentence):
    """Sorts the words then prinits the first and last one."""
    words = sort_sentence(sentence)
    print_first_word(words)
    print_last_word(words)

有什么解决办法吗?

推荐答案

在这个函数中 return 没有正确缩进.

in this function the return is not properly indented.

def break_words(stuff):
    """This function will break up words for us."""
    words = stuff.split(' ')
    return words

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