打字稿类推断 [英] Typescript Class inference

问题描述

有谁知道如何在抽象泛型类中获取当前类?如何像CurrentClass"类型一样引用当前类而不仅仅是抽象类?

Does anyone know how to get the current class in an abstract-generic-class | how to reference the current class like a type "CurrentClass" and not just the abstract class?

原因:我正在编写一个小型库，它应该推断"当前类而不执行作为 CurrentClass"

reason: i'm writing a small library, that should "infer" the current class without doing "as CurrentClass"

abstract class Super {
  public static create(args: keyof CurrentClass) {}
}

class CurrentClass extends Super {}

// to prevent
CurrentClass.create({} as CurrentClass);

我到处搜索，但找不到答案，所以在打字稿中甚至可能吗?

i searched everywhere, but couldnt find an answer to this, so is it even possible in typescript?

这个问题 会解决它，但不适用于静态函数

this question would solve it, but not for static functions

更新:似乎这个是我正在寻找的问题>

Update: it seems that this is the issue i was looking for

推荐答案

通常的解决方法是添加一个类型参数以从调用中推断目标:

The usual workaround is to add a type parameter to infer the target from the call:

abstract class Super {
  s = ""
  public static create<T>(this:new (...a: any[]) => T, args: keyof T) {}
}

class CurrentClass extends Super {
  c = ""
}

// to prevent
CurrentClass.create("c"); // ok
CurrentClass.create("s"); // ok

玩

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