如何避免连续两次返回相同的字符串 [英] How to avoid returning the same string twice in a row

问题描述

我正在使用 Java 开发 SimpleEliza 图表框.我已经完成了老师要求的所有内容，只是我需要对方法 askQuestion 进行编程，以免连续两次从数组中返回相同的字符串.我不确定如何解决这个问题.你能给我一些建议吗.

下面是 simpleEliza 类的代码.为了避免混淆，simpleEliza 从不同的(启动器)类中拉取.不过那应该没关系.

public class SimpleEliza {int questionNumber=0;公共布尔 hasMoreQuestions() {而(真){问题编号++；如果(问题编号 == 6)中断；返回真；}System.out.println("我完了，别管我了.");返回假；}公共字符串 askQuestion(){String[] questionList = {"你好吗?", "你做了这么久吗?","你喜欢这门课吗?", "你叫什么名字?",你对计算机有什么看法?"};返回 questionList[(int)(Math.random()*questionList.length)];}公共字符串听(字符串语句){//正面回应if (statement.toLowerCase().contains("like"))return ("那太好了！");if (statement.toLowerCase().contains ("love"))return ("那太好了！");if (statement.toLowerCase().contains ("excellent"))return ("那太好了！");if (statement.toLowerCase().contains ("good"))return ("那太好了！");//否定响应if (statement.toLowerCase().contains("dislike"))返回(哎呀")；if (statement.toLowerCase().contains("hate"))返回(哎呀")；if (statement.toLowerCase().contains("不喜欢"))返回(呀")；返回嗯嗯"；}}

解决方案

只需保留类中最后一个返回值的索引，然后检查最后一个是否等于当前值.

int lastIndex = -1;//将此全局添加到您的类中，而不是方法中.int currIndex = (int)(Math.random()*questionList.length);做{结果 = questionList[currIndex];}while (lastIndex == currIndex);

顺便说一句，您应该更喜欢我的方法而不是将最后一个字符串作为 Java 缓存整数从 -128 到 127 这将使您的程序使用的内存少于创建用于比较的对象；)

I am working on a SimpleEliza chartbox in Java. I have finished everything that my teacher has required except that I need to program the method askQuestion to not return the same string from the array twice in a row. I am uncertain as how to approach this problem. Can you give me some advice.

Below is the code for the simpleEliza class. Just to avoid confusion, simpleEliza pulls from a different (Launcher) class. That shouldn't matter though.

public class SimpleEliza {
    int questionNumber=0;

    public boolean hasMoreQuestions() {

        while (true) {
            questionNumber ++;
        if (questionNumber == 6) break;
            return true;}
            System.out.println("I'm done leave me alone.");
            return false;   
    }


    public String askQuestion(){
        String[] questionList = {"How are you doing?", "Have you been doing this long?",
                                "Do you like this class?", "What is you name?",
                                "What do you think about computers?"};
        return questionList[(int)(Math.random()*questionList.length)];
    }

    public String listen(String statement){

        // Positive Responses
        if (statement.toLowerCase().contains("like"))
                return ("That's nice!");
        if (statement.toLowerCase().contains ("love"))
                return ("That's nice!");
        if (statement.toLowerCase().contains ("excellent"))
                return ("That's nice!");
        if (statement.toLowerCase().contains ("good"))
                return ("That's nice!");

        //Negative Responses
        if (statement.toLowerCase().contains("dislike"))
                return ("Yikes");
        if (statement.toLowerCase().contains("hate"))
                return ("Yikes");
        if (statement.toLowerCase().contains("do not like"))
                return ("Yikes");

        return "Uh Huh";
    }

}

解决方案

Simply keep an index of the last returned value in your class then check if the last is equals to current.

int lastIndex = -1;//add this global to your class, not the method.

int currIndex = (int)(Math.random()*questionList.length);
do
{
   result = questionList[currIndex];
}
while (lastIndex == currIndex);

By the way you should prefer my method over keeping the last String as Java cache integers from -128 to 127 which will make your program use less memory than creating an object for comparison ;)

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