Unix shell 文件复制扁平化文件夹结构 [英] Unix shell file copy flattening folder structure

问题描述

在 UNIX bash shell(特别是 Mac OS X Leopard)上，将每个具有特定扩展名的文件从文件夹层次结构(包括子目录)复制到同一目标文件夹(没有子文件夹)的最简单方法是什么?

On the UNIX bash shell (specifically Mac OS X Leopard) what would be the simplest way to copy every file having a specific extension from a folder hierarchy (including subdirectories) to the same destination folder (without subfolders)?

显然存在源层次结构中存在重复项的问题.如果它们被覆盖，我不介意.

Obviously there is the problem of having duplicates in the source hierarchy. I wouldn't mind if they are overwritten.

示例:我需要复制以下层次结构中的每个 .txt 文件

Example: I need to copy every .txt file in the following hierarchy

/foo/a.txt
/foo/x.jpg
/foo/bar/a.txt
/foo/bar/c.jpg
/foo/bar/b.txt

到名为dest"的文件夹并获取:

To a folder named 'dest' and get:

/dest/a.txt
/dest/b.txt

推荐答案

在 bash 中:

find /foo -iname '*.txt' -exec cp \{\} /dest/ \;

find 会查找/foo 路径下所有匹配通配符*.txt 的文件，不区分大小写(这就是-iname 的意思).对于每个文件，find 将执行 cp {}/dest/，用找到的文件代替 {}.

find will find all the files under the path /foo matching the wildcard *.txt, case insensitively (That's what -iname means). For each file, find will execute cp {} /dest/, with the found file in place of {}.

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