urllib2.urlopen('ur') 给出错误 [英] urllib2.urlopen('ur') gives error

问题描述

我是 Python 新手，正在尝试提取页面的内容.当我执行 urlopen('http://www.google.com') 时，出现以下错误:

I am new to python and trying to extract the contents of a page. When I do urlopen('http://www.google.com'), I get the following error :

File "<stdin>", line 1, in <module>    
  File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/usr/lib/python2.7/urllib2.py", line 391, in open
    response = self._open(req, data)
  File "/usr/lib/python2.7/urllib2.py", line 409, in _open
    '_open', req)
  File "/usr/lib/python2.7/urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.7/urllib2.py", line 1185, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/usr/lib/python2.7/urllib2.py", line 1160, in do_open
    raise URLError(err)

有什么解决办法吗?

推荐答案

如果您的网络处于脱机状态，则会出现该错误消息

that error message occurs if your net is offline

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