如何交换阵列中的两个值与索引？ [英] How to swap two values in array with indexes?

问题描述

例如，我有一个这样的数组 $阵列=（'A'=＆GT; 2，'B'=大于1，'C'=＆GT; 4）; ，我需要换 A 与 C 来得到这个 $阵列=（ 'C'=→4，'b'=＆GT; 1，'A'=＆GT; 2）; 。 WHT是这样做的，而无需创建新的数组的最佳方式？我知道这是可能的XOR，但我也需要保存索引。

For example i have an array like this $array = ('a' => 2, 'b' => 1, 'c' => 4); and i need to swap a with c to get this $array = ('c' => 4, 'b' => 1, 'a' => 2);. Wht is the best way for doing this without creating new array? I know that it is possible with XOR, but i also need to save indexes.

推荐答案

array_splice 将是完美的，但不幸的是它在插入不preserve键阵列。所以你不得不求助于多一点手工切片和切块：

array_splice would be perfect, but unfortunately it doesn't preserve the keys in the inserted arrays. So you'll have to resort to a little more manual slicing and dicing:

function swapOffsets(array $array, $offset1, $offset2) {
    list($offset1, $offset2) = array(min($offset1, $offset2), max($offset1, $offset2));

    return array_merge(
        array_slice($array, 0, $offset1, true),
        array_slice($array, $offset2, 1, true),
        array_slice($array, $offset1 + 1, $offset2 - $offset1 - 1, true),
        array_slice($array, $offset1, 1, true),
        array_slice($array, $offset2 + 1, null, true)
    );
}

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