选择第一个值以外的值时，如何自动提交下拉列表? [英] How do I auto submit a dropdown when a value is selected other than the first value?

问题描述

当前代码:

<select name='PreviousReceiver' onchange='this.form.submit()'>
     <option value='0'>Contact List</option>
     <option value='1'>blah</option>
     <option value='2'>blah2</option>
     <option value='3'>blah3</option>
</select>

所以我有这个下拉框，当用户点击它时会自动提交.它的工作方式很好，但如果用户选择了第一个值(见上文)，我不希望它提交.

So I have this dropdown box that auto submits when the user clicks it. It works fine the way it is, but I dont want it to submit if the user has the first value selected(see above).

换句话说，如果用户点击联系人列表，那么我不希望它提交表单.

In other words, if the user clicks contact list, then I don't want it to submit the form.

我试过这个:

 onchange="if(this.value != '0') this.form.submit()" 

但这只是让它永远不会激活.

but that just made it never activate.

有什么建议吗?

推荐答案

尝试不使用引号并检查.

Try without quotes and check.

此处演示

<form method="post">
    <select name='PreviousReceiver' onchange='if(this.value != 0) { this.form.submit(); }'>
         <option value='0'>Contact List</option>
         <option value='1'>blah</option>
         <option value='2'>blah2</option>
         <option value='3'>blah3</option>
    </select>
</form>

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