蟒蛇:XLRD；比较列长度 [英] Python : XLRD; compare the columns length

问题描述

我正在使用 xlrd 处理 xls 文件.我的 xls 文件有两列，我的要求是确保两列的行数相同.我从 help() 了解到我们有一个 row_len() 来查找给定索引的行的长度，但找不到 col_len.你能帮忙吗

这是我的代码

from xlrd import open_workbookspread_sheet=open_workbook("simple.xls")sheet1=spread_sheet.sheet_by_index(0)#验证电子表格中的列数如果 sheet1.ncols == 2:对于范围内的 sheet1_rows(sheet1.nrows):对于范围内的 sheet1_cols(sheet1.ncols):value=sheet1.cell(sheet1_rows,sheet1_cols).valuesource=sheet1.cell(sheet1_rows,0).value目的地=sheet1.cell(sheet1_rows,1).value#ignores 源头和目标头如果值不在 ('Source','Destination') 中:打印来源是:%s\n目的地是:%s\n"%(来源，目的地)别的:打印提供的 XLS 无效.检查列数是否为 2"

除了比较下面的一些其他选项，请

<预><代码>>>>打印 len(sheet1.col_values(0))8>>>打印 len(sheet1.col_values(1))8

<小时>

感谢您的回复@alecxe.而不是在我的代码中添加了几行，我在下面找到了一些东西.请告知这是否可行

 >>>打印 len(sheet1.col_values(0))6>>>打印 len(sheet1.col_values(1))6>>>sheet1.col_values(0)[u'A', 1.0, 1.0, 1.0, 1.0, 2.0]>>>sheet1.col_values(1)[u'B', 2.0, 2.0, 2.0, 2.0, '']>>>打印 len(filter(None,sheet1.col_values(1)))5>>>

解决方案

你不能用 len(sheet.col_values(index)) 来测量列(column长度).col_values 长度总是等于 sheet.nrows.

假设您在 input.xls 中有以下内容:

A B1 21 21 21 22

然后 len(sheet.col_values(0)) 将返回 5(以及 len(sheet.col_values(1)))，这是不正确的.应该是 4.

相反，最好使用这样的东西:

from itertools import takewhile导入 xlrddef column_len(工作表，索引):col_values = sheet.col_values(index)col_len = len(col_values)for _ in takewhile(lambda x: not x, reversed(col_values)):col_len -= 1返回 col_lenbook = xlrd.open_workbook("input.xls")sheet = book.sheet_by_index(0)打印 column_len(sheet, 0) # 打印 4打印 column_len(sheet, 1) # 打印 5

希望有所帮助.

I'm using xlrd to work on xls files. My xls file has got two columns and my requirement is to make sure both the columns have got equal number of rows. I learnt from help() that we have got a row_len() to look for the length of a row given with the index, but unable to find any for col_len. Can you please help with any

Here is my code

from xlrd import open_workbook
spread_sheet=open_workbook("simple.xls")
sheet1=spread_sheet.sheet_by_index(0)

#validates the no of columns in the Spread sheet
 if sheet1.ncols == 2:
  for sheet1_rows in range(sheet1.nrows):
    for sheet1_cols in range(sheet1.ncols):
        value=sheet1.cell(sheet1_rows,sheet1_cols).value
        source=sheet1.cell(sheet1_rows,0).value
        destination=sheet1.cell(sheet1_rows,1).value
    #ignores the Source and Destination Headers 
    if value not in ('Source','Destination'):
        print "Source is : %s \nDestination is : %s\n" %    (source,destination)
 else:
  print "XLS provided is not valid. Check the no of columns is 2"

Some other options apart from comparing the below please

>>> print len(sheet1.col_values(0))
8
>>> print len(sheet1.col_values(1))
8

---

Thanks for your reply @alecxe. Instead adding few more lines to my code, I found out something below. please advise will this work out

 >>> print len(sheet1.col_values(0))
 6
 >>> print len(sheet1.col_values(1))
 6
 >>> sheet1.col_values(0)
 [u'A', 1.0, 1.0, 1.0, 1.0, 2.0]
 >>> sheet1.col_values(1)
 [u'B', 2.0, 2.0, 2.0, 2.0, '']
 >>> print len(filter(None,sheet1.col_values(1)))
 5
 >>>

解决方案

You can't use len(sheet.col_values(index)) for measuring how many cells are set in the column (column length). col_values length is always equal to sheet.nrows.

Imagine you have the following in the input.xls:

A B
1 2
1 2
1 2
1 2
  2 

Then len(sheet.col_values(0)) will return 5 (as well as len(sheet.col_values(1))), which is incorrect. Should be 4.

Instead, it's better to use something like this:

from itertools import takewhile
import xlrd


def column_len(sheet, index):
    col_values = sheet.col_values(index)
    col_len = len(col_values)
    for _ in takewhile(lambda x: not x, reversed(col_values)):
        col_len -= 1
    return col_len


book = xlrd.open_workbook("input.xls")
sheet = book.sheet_by_index(0)

print column_len(sheet, 0)  # prints 4
print column_len(sheet, 1)  # prints 5

Hope that helps.

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