用 BeautifulSoup 中的另一个标签替换一个标签 [英] Replace a tag with another tag in BeautifulSoup
本文介绍了用 BeautifulSoup 中的另一个标签替换一个标签的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我试图在 XML 文档中找到一个标签，并用一个新标签完全替换它.我有我认为应该在下面工作的内容:
I'm attempting to find a tag within an XML document, and replace it entirely with a new tag. I've got what I think should work below:
para = monograph.find('para', text='Some text.')
newpara = '<para>Some <emph type="bold">new</emph> text.</para>'
newpara = BeautifulSoup(newpara, 'xml')
para.replaceWith(newpara)
不幸的是，当我运行这个时，我得到:
Unfortunately, when I run this, I'm getting:
Traceback (most recent call last):
File "<input>", line 1, in <module>
File "C:\Python34\lib\site-packages\bs4\element.py", line 211, in replace_with
my_index = self.parent.index(self)
AttributeError: 'NoneType' object has no attribute 'index'
有什么建议吗?
推荐答案
您可以使用 replaceWith() 来实现这一点，这是一种方法:
You can use replaceWith() to achieve this, here is one way how to do it:
In [8]: from bs4 import BeautifulSoup
In [9]: tree = BeautifulSoup('<html><body><div>Foo</div><div>Bar</div><para>Some text.</para></body></html>', 'xml')
In [10]: newpara = '<para>Some <emph type="bold">new</emph> text.</para>'
In [11]: newpara = BeautifulSoup(newpara, 'xml')
# here I use newpara.para as a shortcut to get the <para> element
# as a new BeautifulSoup will include wrapping tags
In [12]: tree.find('para', text='Some text.').replaceWith(newpara.para)
Out[12]: <para>Some text.</para>
In [13]: print tree
<?xml version="1.0" encoding="utf-8"?>
<html><body><div>Foo</div><div>Bar</div><para>Some <emph type="bold">new</emph> text.</para></body></html>
希望这会有所帮助.
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