不使用默认命名空间的没有前缀的 XSL 输出 XML? [英] XSL output XML with no prefix without using the default namespace?
问题描述
我有一个 XSL,我需要按照以下方式生成输出:
I have an XSL where I need to generate output along the lines of this:
<moo xmlns="http://api.example.com">
<foo>1358944586848</foo>
<bar>
<a>1</a>
<b>2</b>
<c>3</c>
</bar>
</moo>
我可以这样做:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://api.example.com">
<xsl:template match="/">
<xsl:element name="moo">
<!-- and so on -->
然而,我有点讨厌在我的 xsl 文件中使用 xsl 前缀,因为我觉得它很混乱.无论如何,使用 XPath 进行选择很容易,因为您可以根据需要将 xpath-default-namespace
设置为您正在转换的任何内容.但是就我所见,没有 element-default-namespace
可用,那么如何以一种好的方式生成所需的输出?
However, I kind of hate using the xsl prefix in my xsl files cause I feel it clutters it up a lot. Selecting with XPath is easy anyways since you can set xpath-default-namespace
to whatever you're transforming from if needed. But there is no element-default-namespace
available as far as I can see, so how can I generate the wanted output in a good way?
我知道我可以做到:
<stylesheet version="2.0"
xmlns="http://www.w3.org/1999/XSL/Transform">
<template match="/">
<element name="moo" namespace="http://api.example.com">
<!-- and so on -->
但随后我必须在我创建的每个元素上显式设置此命名空间,否则它们最终将使用 XSL 命名空间.那么有没有一种干净的方法来创建具有特定命名空间(没有前缀)的元素而不触及 xsl 文件的默认命名空间?
But then I have to set this namespace explicitly on every single element I create, or they will end up with the XSL namespace instead. So is there a clean way to create elements with a certain namespace (without a prefix) and not touching the default namespace of the xsl file?
更新:
觉得namespace-alias
可以做点什么,但是不知道怎么用.试过了,但似乎对输出没有任何影响:
Figured maybe namespace-alias
could do something, but can't figure out how to use it. Tried this, but doesn't seem to make any difference in the output at all:
<stylesheet version="2.0"
xmlns="http://www.w3.org/1999/XSL/Transform"
xmlns:out="http://api.example.com">
<namespace-alias stylesheet-prefix="out" result-prefix=""/>
<template match="/">
<element name="out:moo">
<!-- and so on -->
namespace-alias
的事情可能不是我认为的那样:p
The namespace-alias
thing probably isn't doing what I think it is :p
我使用的最终解决方案,基于 JLRishe 的回答
remove-prefixes.xsl
<?xml version="1.0" encoding="UTF-8"?>
<stylesheet version="2.0" xmlns="http://www.w3.org/1999/XSL/Transform">
<template match="/">
<variable name="result">
<next-match />
</variable>
<apply-templates select="$result" mode="remove-prefixes" />
</template>
<template match="*" priority="1" mode="remove-prefixes">
<element name="{local-name()}" namespace="{namespace-uri()}">
<apply-templates select="@* | node()" mode="remove-prefixes" />
</element>
</template>
<template match="@*|node()" mode="remove-prefixes">
<copy>
<apply-templates select="@* | node()" mode="remove-prefixes" />
</copy>
</template>
</stylesheet>
subject.xsl
<!-- snip -->
<import href="remove-prefixes.xsl" />
<!-- snip -->
推荐答案
您可以做的一件事是将 XSL 的整个结果捕获到一个变量中,然后在结尾处清除其前缀:
One thing you could do is capture the entire result of the XSL in a variable, and then blank out its prefixes at the end:
<stylesheet version="2.0" xmlns="http://www.w3.org/1999/XSL/Transform"
xmlns:p="http://api.example.com">
<output method="xml" indent="yes"/>
<template match="/">
<variable name="result">
<p:moo>
<apply-templates />
</p:moo>
</variable>
<apply-templates select="$result" mode="removePrefix" />
</template>
<template match="root">
<p:something hello="hi">
<element name="p:somethingelse" />
</p:something>
</template>
<template match="p:*" mode="removePrefix">
<element name="{local-name()}" namespace="{namespace-uri()}">
<apply-templates select="@* | node()" mode="removePrefix" />
</element>
</template>
<template match="@* | node()" mode="removePrefix">
<copy>
<apply-templates select="@* | node()" />
</copy>
</template>
</stylesheet>
在此输入上运行时:
<root>
<top />
</root>
它产生:
<moo xmlns="http://api.example.com">
<something hello="hi">
<somethingelse />
</something>
</moo>
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