python在函数中使用yield from [英] python using yield from in a function

问题描述

我有一个类似的列表:

list=['2,130.00','2,140.00','2,150.00','2,160.00']

我想使用像

def f(iterable):
    yield from iterable

和应用

float(item.replace(',','')) for item in iterable

同时使

f(list)

返回

[2130.00,2140.00,2150.00,2160.00]

我知道

[float(x.replace(',','')) for x in list]

在这里工作，但它是了解如何在函数中使用 yield from并同时修改迭代中的项目.也许我必须在函数中使用 *args 和/或 **kwargs，但不确定我有以及如何使用.

works here but it is to understand how to use yield from in a function and modifying items in the iterable at the same time. Maybe i have to use *args and/or **kwargs in the function but not sure i have and how to.

推荐答案

yield from 是一个传递；您正在委托给可迭代对象.将可迭代对象包装在生成器表达式中以转换元素，或者不使用 yield from 而是使用显式循环:

yield from is a pass-through; you are delegating to the iterable. Either wrap the iterable in a generator expression to transform elements, or don't use yield from but an explicit loop:

def f(iterable):
    yield from (i.replace(',', '') for i in iterable)

或

def f(iterable):
    for item in iterable:
        yield item.replace(',', '')

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