android - 如何从另一个布局声明一个小部件? [英] android - how to declare a widget from another layout?

问题描述

我有一个包含类的片段布局，但它需要编辑另一个布局片段中的图像视图.示例:

I have a fragment layout that contains a class, but it needs to edit an imageview that is in another layout fragment. Example:

public class LayoutFragment extends Fragment {
private ImageView imageView;

public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    final View view = inflater.inflate(R.layout.fragment_layout, container, false);

    imageView = view.findViewById(R.id.imageView); // this imageview is not fragment_layout, he is in fragment_layout2

    addChild();

    return view;
}

private void addChild() {
    LayoutInflater inflates = LayoutInflater.from(getContext());
    int id = R.layout.dynamic_layout_budget;
    LinearLayout relativeLayout = (LinearLayout) inflates.inflate(id, null, false);

    imageView.setImageBitmap(bitmap);

    layout.addView(relativeLayout);
      }
}

但是如果我这样做，则会出现尝试在空对象引用上调用虚方法"类型的错误

but if I do this, an error of type "attempt to invoke virtual method on a null object reference"

如何操作另一个片段布局中的图像视图?

How could I manipulate this imageview that is in another fragment layout?

推荐答案

问题可能是因为您作为父母在充气机中支付了 null.

The issue may be because you are paying null as a parent in inflater.

所以不要在

LinearLayout relativeLayout = (LinearLayout) inflates.inflate(id, null, false);

尝试像这样传递一个视图

try passing a view in that like

LinearLayout relativeLayout = (LinearLayout) inflates.inflate(id, layout, false);

但是从您的代码中，我不确定 add 方法中 layout 变量的值是什么.

But from your code I'm not sure that what's the value of layout variable inside add method.

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