如何在文本字段 AngularJS 中验证 IP [英] How to validate an IP in a text field AngularJS

问题描述

如何在 AngularJS 的文本字段中验证 IP?目前我正在使用此代码，但并非在所有情况下都有效.有什么想法吗?

ng-pattern='/^((([01]?[0-9]{1,2})|(2[0-4][0-9])|(25[0]-5]))[.]){3}(([0-1]?[0-9]{1,2})|(2[0-4][0-9])|(25[0]-5]))$/

解决方案

使用:

/\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b/

匹配 0.0.0.0 到 255.255.255.255

如果你想删除 0.0.0.0 和 255.255.255.255 我建议你添加额外的 if 语句.否则正则表达式会太复杂.

观察者示例:

$scope.ip = '1.2.3.4';$scope.$watch(function () {返回 $scope.ip;},函数(新值，旧值){如果 (newVal != '0.0.0.0' &&newVal != '255.255.255.255' &&newVal.match(/\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b/)){//匹配尝试成功} 别的 {//匹配尝试失败}})

<小时>

演示 小提琴

最好的办法是创建指令，例如:

这个例子可能有助于如何为自定义输入创建指令:format-input-value-in-angularjs

How to validate an IP in a textfield in AngularJS ? Currently I am using this code, but its not working in all cases . Any idea ?

ng-pattern='/^((([01]?[0-9]{1,2})|(2[0-4][0-9])|(25[0-5]))[.]){3}(([0-1]?[0-9]{1,2})|(2[0-4][0-9])|(25[0-5]))$/

解决方案

Use:

/\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b/

Matches 0.0.0.0 through 255.255.255.255

If you want to drop 0.0.0.0 and255.255.255.255 I suggest you to add additional if statement. Otherwise the regex will be too complicated.

Example with watcher:

$scope.ip = '1.2.3.4';

    $scope.$watch(function () {
        return $scope.ip;
    },

    function (newVal, oldVal) {            
        if (
            newVal != '0.0.0.0' && newVal != '255.255.255.255' &&
            newVal.match(/\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b/))
        {
             // Match attempt succeeded
        } else {
            // Match attempt failed
        }
    })

---

Demo Fiddle

[Edit]

The best bet is to create directive, something like: <ip-input>

This example might helpful how to create directive for custom input: format-input-value-in-angularjs

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