Java 或 Pig 正则表达式从 UserAgent 字符串中去除值 [英] Java or Pig regex to strip out values from UserAgent string

问题描述

我需要删除用户代理字符串的括号"部分中的第三个和后续值.

I need to strip out the third and subsequent values in the 'bracketed' component of the user agent string.

为了得到

Mozilla/4.0(兼容；MSIE 8.0)

Mozilla/4.0 (compatible; MSIE 8.0)

来自

Mozilla/4.0(兼容；MSIE 8.0；Windows NT 6.0；Trident/4.0；GTB6；SLCC1；.NET CLR 2.0.50727；媒体中心 PC 5.0；.NET CLR 3.5.30729；WinTSI 06.12.NET 2009CLR 3.0.30729；.NET4.0C)

Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.0; Trident/4.0; GTB6; SLCC1; .NET CLR 2.0.50727; Media Center PC 5.0; .NET CLR 3.5.30729; WinTSI 06.12.2009; .NET CLR 3.0.30729; .NET4.0C)

我成功使用了 sed 命令

I successfully use sed command

 sed 's/(\([^;]\+; [^;]\+\)[^)]*)/(\1)/'

我需要使用 Java 正则表达式在 Apache Pig 中获得相同的结果.有人能帮我把上面的 sed 正则表达式改写成 Java 吗?

I need to get the same result in Apache Pig with a Java regex. Could anybody help me to re-write the above sed regular expression into Java?

类似于:

new = FOREACH userAgent GENERATE FLATTEN(EXTRACT(userAgent, 'JAVA REGEX?') as (term:chararray);

推荐答案

我不使用 Pig，但翻阅文档会发现一个 REPLACE 函数包装了 Java 的 replaceAll() 方法.试试这个:

I don't use Pig, but a look through the docs reveals a REPLACE function which wraps Java's replaceAll() method. Try this:

REPLACE(userAgent, '\(([^;]+; [^;]+)[^)]*\)', '($1)')

这应该匹配 UserAgent 字符串的整个括号部分，并用前两个分号分隔的术语替换其内容，就像您的 sed 命令一样.

That should match the whole parenthesized portion of the UserAgent string and replace its contents with just the first two semicolon-separated terms, just like your sed command does.

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