使用 Guzzle 6 上传文件到 API 端点 [英] Upload file using Guzzle 6 to API endpoint

问题描述

我可以使用 Postman 将文件上传到 API 端点.

I am able to upload a file to an API endpoint using Postman.

我正在尝试将其转换为从表单上传文件，使用 Laravel 上传并使用 Guzzle 6 发布到端点.

I am trying to translate that into uploading a file from a form, uploading it using Laravel and posting to the endpoint using Guzzle 6.

它在 Postman 中的外观截图(我故意省略了 POST URL)

Screenshot of how it looks in Postman (I purposely left out the POST URL)

以下是您在 POSTMAN 中单击生成代码"链接时生成的文本:

Below is the text it generates when you click the "Generate Code" link in POSTMAN:

POST /api/file-submissions HTTP/1.1
Host: strippedhostname.com
Authorization: Basic 340r9iu34ontoeioir
Cache-Control: no-cache
Postman-Token: 6e0c3123-c07c-ce54-8ba1-0a1a402b53f1
Content-Type: multipart/form-data; boundary=----WebKitFormBoundary7MA4YWxkTrZu0gW

----WebKitFormBoundary7MA4YWxkTrZu0gW
Content-Disposition: form-data; name="FileContents"; filename=""
Content-Type: 


----WebKitFormBoundary7MA4YWxkTrZu0gW
Content-Disposition: form-data; name="FileInfo"

{ "name": "_aaaa.txt", "clientNumber": "102425", "type": "Writeoff" }
----WebKitFormBoundary7MA4YWxkTrZu0gW

以下是用于保存文件和其他信息的控制器功能.文件上传正确，我可以获取文件信息.

Below is controller function for saving the file and other info. The file uploads correctly, I am able to get the file info.

我认为我遇到的问题是使用正确的数据设置 multipart 和 headers 数组.

I think the problem I am having is setting the multipart and headers array with the correct data.

public function fileUploadPost(Request $request)
{
    $data_posted = $request->input();
    $endpoint = "/file-submissions";
    $response = array();
    $file = $request->file('filename');
    $name = time() . '_' . $file->getClientOriginalName();
    $path = base_path() .'/public_html/documents/';

    $resource = fopen($file,"r") or die("File upload Problems");

    $file->move($path, $name);

    // { "name": "test_upload.txt", "clientNumber": "102425", "type": "Writeoff" }
    $fileinfo = array(
        'name'          =>  $name,
        'clientNumber'  =>  "102425",
        'type'          =>  'Writeoff',
    );

    $client = new \GuzzleHttp\Client();

    $res = $client->request('POST', $this->base_api . $endpoint, [
        'auth' => [env('API_USERNAME'), env('API_PASSWORD')],
        'multipart' => [
            [
                'name'  =>  $name,
                'FileContents'  => fopen($path . $name, 'r'),
                'contents'      => fopen($path . $name, 'r'),
                'FileInfo'      => json_encode($fileinfo),
                'headers'       =>  [
                    'Content-Type' => 'text/plain',
                    'Content-Disposition'   => 'form-data; name="FileContents"; filename="'. $name .'"',
                ],
                // 'contents' => $resource,
            ]
        ],
    ]);

    if($res->getStatusCode() != 200) exit("Something happened, could not retrieve data");

    $response = json_decode($res->getBody());

    var_dump($response);
    exit();
}

我收到的错误，它是如何使用 Laravel 的调试视图显示的屏幕截图:

The error I am receiving, screenshot of how it displays using Laravel's debugging view:

推荐答案

您发布数据的方式错误，因此接收到的数据格式错误.

The way you are POSTing data is wrong, hence received data is malformed.

Guzzle 文档:

multipart 的值是一个关联数组的数组，每个包含以下键值对:

The value of multipart is an array of associative arrays, each containing the following key value pairs:

name:(字符串，必填)表单字段名称

name: (string, required) the form field name

contents:(StreamInterface/resource/string, required) 使用的数据表单元素.

contents:(StreamInterface/resource/string, required) The data to use in the form element.

headers:(数组)与表单元素一起使用的自定义标题的可选关联数组.

headers: (array) Optional associative array of custom headers to use with the form element.

filename:(字符串)可选字符串作为部分中的文件名发送.

filename: (string) Optional string to send as the filename in the part.

使用上述列表之外的键并设置不必要的标头而不将每个字段分成一个数组将导致发出错误请求.

Using keys out of above list and setting unnecessary headers without separating each field into one array will result in making a bad request.

$res = $client->request('POST', $this->base_api . $endpoint, [
    'auth'      => [ env('API_USERNAME'), env('API_PASSWORD') ],
    'multipart' => [
        [
            'name'     => 'FileContents',
            'contents' => file_get_contents($path . $name),
            'filename' => $name
        ],
        [
            'name'     => 'FileInfo',
            'contents' => json_encode($fileinfo)
        ]
    ],
]);

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