GetAsyncKeyState 和 VirtualKeys/使用 JNA (JAVA) 的特殊字符 [英] GetAsyncKeyState and VirtualKeys/special characters using JNA (JAVA)

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问题描述

我正在开发一种可在全屏游戏中使用的双向私人聊天.

I am working on a two-way private chat that will work in a full screen game.

这是为了让用户可以在屏幕顶部的半透明文本框中输入即使它没有焦点.

This is required to let the user to type into a semi-transparent textbox at the top of the screen even when it doesn't have focus.

使用以下代码,我可以检测到所有物理键,但使用虚拟键时会遇到困难.

Using the following code, I can detect ALL physical keys, but have a tough time with virtual keys.

SHIFT 被检测到.

2 被检测到.

但是 Shift + 2 都被检测为单独的键(即使 [SHIFT+2] 在我的键盘上给出了 @ ).IE:程序输出 SHIFT 和 2,但不是它们产生的:@.

However Shift + 2 are detected both as separate keys (Even though [SHIFT+2] gives @ on my keyboard). IE: The program outputs both SHIFT, and 2, but not what they produce: @.

问题是,我将如何根据键盘转换为字符?例如:

The problem is, how will I convert to a character depending on the keyboard? For example:

  • 在英国键盘上,SHIFT+2 会给我 "(引号).
  • 在美式键盘上,SHIFT +2 会给我 @.
  • On a UK Keyboard, SHIFT+2 will give me " (quotes).
  • On a US keyboard, SHIFT +2 will give me @.

如何根据键盘转换为特定字符?

How can I convert to a specific character depending on the keyboard?

这是目前的代码:

static interface User32 extends Library {
    public static User32 INSTANCE = (User32) Native.loadLibrary("User32", User32.class);

    short GetAsyncKeyState(int key);
    short GetKeyState(int key);

    IntByReference GetKeyboardLayout(int dwLayout);
    int MapVirtualKeyExW (int uCode, int nMapType, IntByReference dwhkl);

    boolean GetKeyboardState(byte[] lpKeyState);

    int ToUnicodeEx(int wVirtKey, int wScanCode, byte[] lpKeyState, char[] pwszBuff, int cchBuff, int wFlags, IntByReference dwhkl);

}



public static void main(String[] args)  {   
    long currTime = System.currentTimeMillis();

    while (System.currentTimeMillis() < currTime + 20000)
    {
        for (int key = 1; key < 256; key++)
            {
                if (isKeyPressed(key)) 
                    getKeyType(key);
            }
    }
}



private static boolean isKeyPressed(int key)
{
    return User32.INSTANCE.GetAsyncKeyState(key) == -32767;
}



private static void getKeyType(int key)
{

    boolean isDownShift = (User32.INSTANCE.GetKeyState(VK_SHIFT) & 0x80) == 0x80;
    boolean isDownCapsLock = (User32.INSTANCE.GetKeyState(VK_CAPS)) != 0;


    byte[] keystate = new byte[256];
    User32.INSTANCE.GetKeyboardState(keystate); 


    IntByReference keyblayoutID = User32.INSTANCE.GetKeyboardLayout(0);
    int ScanCode  = User32.INSTANCE.MapVirtualKeyExW(key, MAPVK_VK_TO_VSC, keyblayoutID);






    char[] buff = new char[10];

    int bufflen = buff.length;
    int ret = User32.INSTANCE.ToUnicodeEx(key, ScanCode, keystate, buff, bufflen, 0, keyblayoutID);


    switch (ret)
    {
        case -1: 
            System.out.println("Error");
        break;

        case 0:  // no translation

        break;

        default: 
        System.out.println("output=" + String.valueOf(buff).substring(0, ret));
    }




}

它工作正常并输出按下的键,但不适用于 Shift + 组合.我意识到我可以执行切换"并将 Shift+3 更改为£",但这不适用于不同的键盘.

It works fine and outputs the keys pressed, but doesn't work with Shift + combinations. I realize that I could do a "Switch" and change Shift+3 to "£", but this will not work with different keyboards.

推荐答案

我明白了.经过很多很多小时的搜索,我设法创建了一种方法,可以将组合转换为当前键盘布局上的组合.它不处理死键(例如重音符号),但它会捕获我需要它捕获的所有 [SHIFT+Combinations].

I got it. After many, many, many hours of searching, I managed to create a method that converts the combination to what it should be on the current keyboard layout. It doesn't deal with dead-keys (such as accents), but it catches all the [SHIFT+Combinations] that I need it to catch.

要使用它,请按如下方式调用它:

To use it, call it as follows:

getCharacter(int vkCode, boolean shiftKeyPressed);

所以,看这个魔术.如果我想获得 SHIFT+3 在我的键盘上给我的东西(£),我使用:

So, watch this magic. If I want to get what SHIFT+3 will give me on my keyboard (£), I use:

getCharacter(KeyEvent.VK_3, true);

代码如下:

public static char getCharacter(int vkCode, boolean shiftKeyPressed)
{

    byte[] keyStates = new byte[256]; //Create a keyboard map of 256 keys

    if (shiftKeyPressed)
    {
        keyStates[16]=-127; //Emulate the shift key being held down
        keyStates[160]=-128; //This needs to be set as well
    }

    IntByReference keyblayoutID = User32.INSTANCE.GetKeyboardLayout(0); //Load local keyboard layout

    int ScanCode  = User32.INSTANCE.MapVirtualKeyExW(vkCode, MAPVK_VK_TO_VSC, keyblayoutID); //Get the scancode

    char[] buff = new char[1];

    int ret = User32.INSTANCE.ToUnicodeEx(vkCode, ScanCode, keyStates, buff, 1, 0, _currentInputLocaleIdentifier);

    switch (ret)
    {
    case -1: //Error
        return (char) -1;

    case 0:  //No Translation
        return (char) 0;

    default: //Returning key...
        return buff[0];
    }
}

以下是声明:

final static int MAPVK_VK_TO_VSC = 0;
static IntByReference _currentInputLocaleIdentifier; 

static interface User32 extends Library {

    public static User32 INSTANCE = (User32) Native.loadLibrary("User32", User32.class);


    IntByReference GetKeyboardLayout(int dwLayout);
    int MapVirtualKeyExW (int uCode, int nMapType, IntByReference dwhkl);

    boolean GetKeyboardState(byte[] lpKeyState);

    int ToUnicodeEx(int wVirtKey, int wScanCode, byte[] lpKeyState, char[] pwszBuff, int cchBuff, int wFlags, IntByReference dwhkl);

}

非常感谢 BrendanMcK,他帮助我找到了这个解决方案.

A big thank you to BrendanMcK, who helped me to get to this solution.

这篇关于GetAsyncKeyState 和 VirtualKeys/使用 JNA (JAVA) 的特殊字符的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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