使用 array_diff 比较两个数组 [英] Comparing two arrays with array_diff

问题描述

我有以下代码，我正在尝试将两个数组与 array_diff 进行比较，但是我一直没有得到任何结果.我不确定这是否重要，但数组中有很多字段，我真的只想比较 1 个字段......这可能吗?我错过了什么?

I have the following code and am trying to compare two array's with array_diff however I keep getting no results. I not sure if it matters, but there are many fields in the array and I really only want to compare 1 field...is this possible? what am I missing?

<?php
$json = file_get_contents("http://ebird.org/ws1.1/data/obs/region/recent?rtype=subnational1&r=US-AZ&back=7&fmt=json");
$json2 = file_get_contents("http://ebird.org/ws1.1/data/obs/region/recent?rtype=subnational1&r=US-NV&back=7&fmt=json");

$array1 = json_decode($json, TRUE);
$array2 = json_decode($json2, TRUE);

if ( $array1 == $array2 ) {
echo 'There are no differences';
}else 
var_dump(array_diff($array2, $array1));
echo 'they are different';

?>

推荐答案

您将需要相互检查数组:

You will need to check the arrays against each other:

$Array_1 = array (1,2,3,4,5);
$Array_2 = array(1,2,3,4,5,6);

print_r(array_diff($Array_1,$Array_2));

将输出:

Array
(
)

鉴于:

 print_r(array_diff($Array_2,$Array_1));

将输出:

Array
(
    [5] => 6
)

所以这可能是一个解决方案:

So this might be a solution:

function ArrayDiff ($Array_1, $Array_2){
    $Compare_1_To_2 = array_diff($Array_1,$Array_2);
    $Compare_2_To_1 = array_diff($Array_2,$Array_1);
    $Difference_Array = array_merge($Compare_1_To_2,$Compare_2_To_1);
    return $Difference_Array;

}

print_r(ArrayDiff($Array_1,$Array_2));

输出:

Array
(
    [0] => 6
)

<小时>

将其放入 if 语句中:

---

Putting this into an if statement:

$Differences = ArrayDiff($Array_2,$Array_1);
if (count($Differences) > 0){
    echo 'There Are Differences Between The Array:';
    foreach ($Differences AS $Different){
        echo "<br>".$Different;
    }

所有示例和代码都基于开始时的数组($Array_1 和 $Array_2)

All the examples and code is based off the arrays at the start ($Array_1 and $Array_2)

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