Google Feed API - 返回媒体:缩略图 [英] Google Feed API - returning media:thumbnail

问题描述

我目前正在使用 Google Feed API 并尝试从 RSS 提要(media:thumbnail")中检索缩略图

I'm currently using the Google Feed API and attempting to retrieve a thumbnail from an RSS feed ("media:thumbnail")

RSS 提要中的 media:thumbnail 行如下所示:

The media:thumbnail line in the RSS feed looks like this:

<media:thumbnail url="http://anyurl.com/thumbnailname.jpg" width="150" height="150"/>

注意:缩略图不属于 media:group

脚本如下所示:

google.load("feeds", "1");

function initialize() {
  var feed = new google.feeds.Feed("http://website.com/news/feed/");
  feed.setNumEntries(20);               
  feed.load(function(result) {
    if (!result.error) {
      var container = document.getElementById("feed");
      for (var i = 0; i < result.feed.entries.length; i++) {
        var entry = result.feed.entries[i];
        var div = document.createElement("div");
        div.appendChild(document.createTextNode(entry.title));
        div.appendChild(document.createTextNode(entry.link));
        container.appendChild(div);
      }
    }
  });
}
google.setOnLoadCallback(initialize);

</script>

TITLE 和 LINK 返回得很好.但我在 Feed API 文档中没有看到任何关于返回 media:thumbnail 的内容——或者特别是它的 URL.

The TITLE and the LINK are returning just fine. But I don't see anything in the Feed API docs about returning media:thumbnail -- or specifically it's URL.

有人知道我如何使用提要 API 返回缩略图网址吗?

Anyone know how I might return the thumbnail URL using the feed API?

推荐答案

UseMIXED_FORMAT 并使用 javascript 搜索 media:thumbnail 网址:

UseMIXED_FORMAT and search the media:thumbnail urls with javascript:

<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">

google.load("feeds", "1");

function initialize() {
    var feed = new google.feeds.Feed('http://channel9.msdn.com/Feeds/RSS');
    feed.setResultFormat(google.feeds.Feed.MIXED_FORMAT);
    feed.setNumEntries(25);
    feed.load(function(result) {
    if (!result.error) {
      for (var i = 0; i < result.feed.entries.length; i++) {
        var entry = result.feed.entries[i];
        var mediaEntries = entry.xmlNode.getElementsByTagNameNS('*','thumbnail');
        for (var j = 0; j < mediaEntries.length; j++) {
            var mediaEntry = mediaEntries[j];
            var mediaThumbnailUrl = mediaEntry.attributes.getNamedItem('url').value
            console.log(mediaThumbnailUrl);
        }
      }
    }
  });
}
google.setOnLoadCallback(initialize);

</script> 

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