我如何在 python 请求中将图像作为参数传递,并将 url 作为第二个参数传递? [英] how i can pass image as argument in python request along with url as 2nd argument?
问题描述
我想使用请求和 url 将图像从视图传递到 api.
Hi i want to pass image from view to api using request,with url.
这是我的代码:
def processImage(request):
image=request.FILES['image']
params = {'image': image }
url='http://127.0.0.1:8000/idealweight/'
outPut_Data=requests.post(url,params=params)
//我也试过这个
img=image
然后通过:
outPut_Data=requests.post(url,img)
但没有奏效.这会在 imgFinalPro 中导致错误,传递的参数很少.
but did not worked.and this gives error in imgFinalPro few arguments passed.
我正在调用这个 imgFinalPro 函数,在这里我想接收图像:
I am calling this imgFinalPro function And here I want to receive the image:
def imgFinalPro(request,img):
print(request)
# image=request.FILES['image']
# image=img
image=request.FILES['image']
我如何在这里接收图像?可以用于进一步处理吗?
How I can receive the image here? CAn use for further processing?
推荐答案
将文件发送到 files 字段而不是 params.
Send your files inside files field not inside params.
def processImage(request):
image=request.FILES['image']
files = {'image': image }
url='http://127.0.0.1:8000/idealweight/'
outPut_Data=requests.post(url, files=files)
我假设 imgFinalPro
是您发布请求的控制器.您无法将图像作为控制器的参数.图片附在您的要求中
I Assume imgFinalPro
is your controller for post request. You can't get the image as params of your controller. The image is attached with your request
def imgFinalPro(request):
print(request)
# image=request.FILES['image']
# image=img
image=request.FILES['image']
这篇关于我如何在 python 请求中将图像作为参数传递,并将 url 作为第二个参数传递?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!