如何将数组参数传递给 Bash 脚本 [英] How to pass an array argument to the Bash script

问题描述

令我惊讶的是，我在搜索了 1 小时后没有找到答案.我想像这样将数组传递给我的脚本:

It is surprising me that I do not find the answer after 1 hour search for this. I would like to pass an array to my script like this:

test.sh argument1 array argument2

我不想把它放在另一个 bash 脚本中，如下所示:

I DO NOT want to put this in another bash script like following:

array=(a b c)
for i in "${array[@]}"
do
  test.sh argument1 $i argument2
done

推荐答案

Bash 数组不是一流的值"——你不能像一个东西"一样传递它们.

Bash arrays are not "first class values" -- you can't pass them around like one "thing".

假设 test.sh 是一个 bash 脚本，我会这样做

Assuming test.sh is a bash script, I would do

#!/bin/bash
arg1=$1; shift
array=( "$@" )
last_idx=$(( ${#array[@]} - 1 ))
arg2=${array[$last_idx]}
unset array[$last_idx]

echo "arg1=$arg1"
echo "arg2=$arg2"
echo "array contains:"
printf "%s\n" "${array[@]}"

并像调用它一样

test.sh argument1 "${array[@]}" argument2

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