Java - 创建一个方法数组 [英] Java - Creating an array of methods

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问题描述

我正在为学校的进步设计一个基于文本的冒险游戏.我将每个级别"设置为一个类,并将每个可探索区域(节点)设置为相应类中的一个方法.

I'm designing a text-based adventure game for a school progress. I have each "level" set up as a class, and each explorable area (node) as a method within the appropriate class.

困扰我的是从一个节点移动到另一个节点的代码.因为每个节点最多连接到四个其他节点,所以我必须在每个方法中重复一段极其相似的代码块.

What's messing with me is the code to move from one node to another. Because each node is connected to up to four other nodes, I have to repeat an extremely similar block of code in each method.

我更喜欢在每个节点的开头包含一组方法,如下所示:

What I'd prefer to do is include an array of methods at the beginning of each node, like this:

public static void zero()
{
    ... adjacentNodes[] = {one(), two(), three(), four()};
}

然后将该数组发送到通用方法,并让它将播放器发送到正确的节点:

And then send that array to a generic method, and have it send the player to the right node:

public static void move(...[] adjacentNodes, int index)
{
    adjacentNodes[index];
}

我简化了我的代码,但这是总体思路.这可能吗?

I simplified my code, but that's the general idea. Is this possible?

推荐答案

每当您想到函数指针时,您都会使用适配器模式(或变体)转换为 Java.应该是这样的:

Whenever you think of pointer-to-function, you translate to Java by using the Adapter pattern (or a variation). It would be something like this:

public class Node {
    ...
    public void goNorth() { ... }
    public void goSouth() { ... }
    public void goEast() { ... }
    public void goWest() { ... }

    interface MoveAction {
        void move();
    }

    private MoveAction[] moveActions = new MoveAction[] {
        new MoveAction() { public void move() { goNorth(); } },
        new MoveAction() { public void move() { goSouth(); } },
        new MoveAction() { public void move() { goEast(); } },
        new MoveAction() { public void move() { goWest(); } },
    };

    public void move(int index) {
        moveActions[index].move();
    }
}

这篇关于Java - 创建一个方法数组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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