C++ 反向数组 [英] C++ Reverse Array

问题描述

在 C++ 中，我需要:

In C++, I need to:

• 从用户输入中读取字符串并将其放入字符数组 [完成]
• 然后将该数组传递给函数 [done]
• 该函数应该颠倒字符的顺序[问题！]
• 然后，回到 main()，它显示带有新反转字符的原始数组.

• Read in a string from user input and place it into a char array [done]
• Then pass that array to a function [done]
• The function is supposed to reverse the order of characters [problem!]
• Then, back in the main(), it displays that original array with the newly reversed characters.

我在创建实际执行反向操作的函数时遇到问题，因为我有一些限制:

I'm having trouble creating the function that actually does the reversing because I have some restrictions:

• 我不能有任何本地数组变量.
• 也没有指针

我的函数只传入原始数组，即:

My function is only passing in the original array ie:

void reverse(char word[])

这是我目前的代码库:

void reverse(char word[]);

void main() 
{
  char word[MAX_SIZE];

  cout << endl << "Enter a word : ";
  cin >> word; 
  cout << "You entered the word " << word << endl;

  reverse(word); 

  cout << "The word in reverse order is " << word << endl;
}

void reverse(char myword[]) 
{
  int i, temp;
  j--;

  for(i=0;i<(j/2);i++) 
  {
    temp      = myword[i];
    myword[i] = myword[j];
    myword[j] = temp; 

    j--; 
  }
}

推荐答案

尽管这看起来很像功课，但我可以建议:

Despite this looking quite homeworky, may I suggest:

void reverse(char word[])
{
    int len=strlen(word);
    char temp;
    for (int i=0;i<len/2;i++)
    {
            temp=word[i];
            word[i]=word[len-i-1];
            word[len-i-1]=temp;
    }
}

或者，更好的是，经典的 XOR 实现:

or, better yet, the classic XOR implementation:

void reverse(char word[])
{
    int len=strlen(word);
    for (int i=0;i<len/2;i++)
    {
        word[i]^=word[len-i-1];
        word[len-i-1]^=word[i];
        word[i]^=word[len-i-1];
    }
}

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