求矩阵中一点到矩阵中所有其他点的距离 [英] Find the distance from one point in a matrix to all other points in a matrix

问题描述

我有一个矩阵a，我想计算从一个点到所有其他点的距离.所以实际上结果矩阵应该有一个零(在我选择的点上)并且应该显示为围绕该特定点的某种数字圆圈.

I have a matrix a and I want to calculate the distance from one point to all other points. So really the outcome matrix should have a zero (at the point I have chosen) and should appear as some sort of circle of numbers around that specific point.

这是我已经拥有的，但我似乎无法得到正确的结果.

This is what I have already but I cant seem to get the correct outcome.

a = [1 2 3 4 5 6 7 8 9 10]

for i = 2:20
    a(i,:) = a(i-1,:) + 1;
end

N = 10

for I = 1:N
    for J = 1:N
        dx = a(I,1)-a(J,1);
        dy = a(I,2)-a(J,2);
        distance(I,J) = sqrt(dx^2 + dy^2)
    end
end

推荐答案

这正是我要找的，但感谢所有的建议.

This is what i was looking for, but thanks for all the suggestions.

A = rand(5, 5);
select_cell = [3 3];
distance = zeros(size(A, 1), size(A, 2));
for i = 1:size(A, 1)
    for j = 1:size(A, 2)
        distance(i, j) = sqrt((i - select_cell(1))^2 + (j - select_cell(2))^2);
    end
end
disp(distance)

您也可以通过使用矢量化来改进它:

Also you can improve it by using vectorisation:

distances = sqrt((x-xCenter).^2+(y-yCenter).^2

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