从 java web start 使用 CXF web 服务 [英] Using CXF web service from java web start

问题描述

更新:我已将我的问题提交到 CXF 用户的邮件列表，此处.

UPDATE: I have submitted my question to the CXF User's mailing list, here.

更新:我目前已经签署了我所有的罐子.我似乎仍然无法以可以找到 WSDL 的方式设置 CXF.我的最后一次尝试是将 WSDL 放在我的 WAr 文件中，以便我可以通过 Web 浏览器访问它.我将客户端内部的 wsdllocation 设置为 URL (http://www.example.com/应用程序/example.wsdl).我现在收到以下异常:

UPDATE: I have currently signed all of my jars. I still can't seem to get CXF setup in a way that it can find the WSDL. My last attempt was to place the WSDL inside of my WAr file so I can access it through a web browser. I set the wsdllocation inside of the client to the URL (http://www.example.com/app/example.wsdl). I am now getting the following exception:

Exception in thread "AWT-EventQueue-0" java.lang.ExceptionInInitializerError
at com.sun.xml.internal.ws.util.xml.XmlUtil.createDefaultCatalogResolver(Unknown Source)
at com.sun.xml.internal.ws.client.WSServiceDelegate.parseWSDL(Unknown Source)
at com.sun.xml.internal.ws.client.WSServiceDelegate.<init>(Unknown Source)
at com.sun.xml.internal.ws.client.WSServiceDelegate.<init>(Unknown Source)
at com.sun.xml.internal.ws.spi.ProviderImpl.createServiceDelegate(Unknown Source)
at javax.xml.ws.Service.<init>(Unknown Source)

谷歌搜索几乎没有发现这一点.

Googling has turned up pretty much nothing on this.

我正在使用 Apache CXF 从给定的 WSDL 创建 Web 服务客户端.我遇到了问题，但是在尝试访问该服务时，出现此异常:

I am creating a web service client from a given WSDL using Apache CXF. I am running into problems however when trying to access the service, I get this exception:

Can not initialize the default wsdl from ../resource/example.wsdl
Exception in thread "AWT-EventQueue-0" java.security.AccessControlException: access denied (java.util.PropertyPermission user.dir read)
at java.security.AccessControlContext.checkPermission(Unknown Source)
at java.security.AccessController.checkPermission(Unknown Source)
at java.lang.SecurityManager.checkPermission(Unknown Source)
at java.lang.SecurityManager.checkPropertyAccess(Unknown Source)

我没有签署我的 web start 应用程序，也不想签署，因为我没有从客户端的机器访问任何资源.提到的 WSDL 打包在我的 jar 中.问题是由 CXF 生成的客户端代码引起的:

I am not signing my web start application, and would prefer not to since I am not accessing any resources from the client's machine. The WSDL mentioned is packaged within my jar. The problem is caused by this from the CXF generated client code:

    URL url = null;
    try {
        url = new URL("../resource/example.wsdl");
    } catch (MalformedURLException e) {
        System.err.println("Can not initialize the default wsdl from ../resource/example.wsdl");
        // e.printStackTrace();
    }
    WSDL_LOCATION = url;

我怎样才能正确地将 CXF 指向这个 WSDL?我也担心类上的WebService注解:

How can I correctly point CXF to this WSDL? I am also worried about the WebService annotation on the class:

@WebServiceClient(name = "Example", 
              wsdlLocation = "../resource/example.wsdl",
              targetNamespace = "http://services.example.com/") 

我还需要更改吗?

推荐答案

经过几次错误和实验后，我设法让一切正常工作.首先，确保 cxf.jar 和 wsdl4j.jar 实际上在您的类路径上.我以为我已经验证了这一点，但是因为我通过 webstart 从一个 jar 中实例化客户端，该 jar 本身打包在 WAR 中，所以我在构建过程中弄乱了 cxf 运行时的位置.此外，在指定 wsdl 位置时，我必须使用 "classpath:my.wsdl".我让自己很轻松，只是将 wsdl 放在与我的源相同的位置.

After a few mistakes and experimentation, I have managed to get everything to work properly. First, MAKE SURE that cxf.jar and wsdl4j.jar are actually on your classpath. I thought I had verified this, but because I was instantiating the client from inside a jar via webstart that was in itself packed in a WAR, I messed up the placement of the cxf runtime in my build process. Also, when specifying the wsdl location, I had to use "classpath:my.wsdl". I made it easy on myself and just put the wsdl in the same location as my source.

希望这能帮助那些可能在某个时候做同样事情的人！

Hope this helps someone who might do the same thing at somepoint!

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