如何使用动态参数启动 Java Web 启动应用程序 [英] How to launch a Java Web start application with dynamic parameters

问题描述

我正在尝试将 Java 小程序迁移到 Java Web 启动应用程序.小程序是从带有多个参数的 JavaScript 激活的，有些参数不是硬编码的 (sessionId, tempFilePath):

I'm trying to migrate a Java applet to a Java web start application. The applet was activated from a JavaScript with several parameters, some are not hard-coded (sessionId, tempFilePath):

deployJava.runApplet(attributes, parameters);

为了迁移小程序，我使用了一个带有 applet-desc 标记的简单 JNLP 文件.从我调用的 JavaScript 中:

In order to migrate the applet I'm using a simple JNLP file with applet-desc tag. And from the JavaScript I call:

deployJava.launchWebStartApplication('$jnlp_path');

我只是不明白如何将 JavaScript 创建的参数传递给 Web 启动应用程序.

I just can't understand how to pass to the web start application the parameters that were created by the JavaScript.

推荐答案

好的，原来使用 deployJava.launchWebStartApplication(...) 会触发 Chrome 和 IE 中的安全限制.
我所做的是一种解决方法:我向我的服务器发送了一个 HTTP 请求，服务器的响应是一个 JNLP 内容.
在服务器端，我在运行时编辑 JNLP，每次插入所需的参数.
当浏览器收到 JNLP 内容时，它们会触发下载所需的 jar.
就是这样！

OK, so it turns out that using deployJava.launchWebStartApplication(...) triggers security restrictions in Chrome and IE.
What I did is kind of work around: I sent an HTTP request to my server and the server's response was a JNLP content.
On the server side, I edited the JNLP on runtime and each time I inserted the required parameters.
When the browsers receive the JNLP content they trigger the download of the required jar.
And that's it!

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