Java:来自 unix 时间戳的日期 [英] Java: Date from unix timestamp

问题描述

我需要将 unix 时间戳转换为日期对象.
我试过这个:

java.util.Date time = new java.util.Date(timeStamp);

时间戳值为:1280512800

日期应该是2010/07/30 - 22:30:00"(因为我是通过 PHP 得到的)但我得到的是 Thu Jan 15 23:11:56 IRST 1970.

应该怎么做?

解决方案

对于 1280512800，乘以 1000，因为 java 需要毫秒:

java.util.Date time=new java.util.Date((long)timeStamp*1000);

如果你已经有毫秒，那么只需 new java.util.Date((long)timeStamp);

来自文档:><块引用>

分配一个 Date 对象并初始化它以表示指定的毫秒数标准基准时间称为纪元"，即 1970 年 1 月 1 日，格林威治标准时间 00:00:00.

I need to convert a unix timestamp to a date object.
I tried this:

java.util.Date time = new java.util.Date(timeStamp);

Timestamp value is: 1280512800

The Date should be "2010/07/30 - 22:30:00" (as I get it by PHP) but instead I get Thu Jan 15 23:11:56 IRST 1970.

How should it be done?

解决方案

For 1280512800, multiply by 1000, since java is expecting milliseconds:

java.util.Date time=new java.util.Date((long)timeStamp*1000);

If you already had milliseconds, then just new java.util.Date((long)timeStamp);

From the documentation:

Allocates a Date object and initializes it to represent the specified number of milliseconds since the standard base time known as "the epoch", namely January 1, 1970, 00:00:00 GMT.

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