如何显示存储在 MySql 数据库中的 BLOB 图像? [英] How to display an BLOB image stored in MySql database?
问题描述
我试图在 MySql 中显示上传到我的商店"表的最后 5 张图像.我是 PHP 和数据库的完全菜鸟，我已经阅读了很多关于如何做到这一点但没有运气的文章.
I am trying to display the last 5 images uploaded to my "store" table in MySql. I'm a complete noob to PHP and databases and i've been reading a lot on how to do this but no luck.
我可以一次存储和显示一张图片，但我希望能够有一个画廊来显示最近上传的 5 张图片.
I can store and display pictures one at a time but i'd like to be able to have a gallery of sorts to show the last 5 uploaded.
非常感谢任何建议或帮助，谢谢！
any advice or help would be greatly appreciated thanks!
附言我知道像这样将图片存储到数据库中是不受欢迎的，但这个项目只是为了练习.
p.s. I know it frowned upon to store pictures to a database like this but this project is just for practice.
index.php
<!DOCTYPE html>
<html>
<head>
<title>Project One</title>
</head>
<body>
<form action="index.php" method="POST" enctype="multipart/form-data">
File:
<input type="file" name="image"> <input type="submit" value="Upload">
<form>
<p />
<?php
//connect to database
(connect to server)
(select correct DB)
//file properties
$file = $_FILES['image']['tmp_name'];
if (!isset($file))
echo "please select an image.";
else
{
$image = addslashes(file_get_contents($_FILES['image']['tmp_name']));
$image_name = $_FILES['image']['name'];
$image_size = getimagesize($_FILES['image']['tmp_name']);
if($image_size==FALSE)
echo "That's not an image.";
else
{
if (!$insert = mysql_query("INSERT INTO store VALUES ('', '$image_name', '$image')"))
echo "Problem Uploading Image.";
else
{
$lastid = mysql_insert_id();
echo "Image uploaded. <p />Your image:<p /><img src=get.php?id=$lastid>";
}
}
}
?>
<p />
<p />
<a href="http://WEBSITE.com/gallery.php"> Go to Gallery </a>
</body>
</html>
get.php
<?php
//connect to database
(connect to server)
(select correct DB)
$id = addslashes($_REQUEST['id']);
$image = mysql_query("SELECT * FROM store WHERE id=$id");
$image = mysql_fetch_assoc($image);
$image = $image['image'];
header("Content-type: image/jpeg");
echo $image;
?>
推荐答案
这是我很久以前想做的事情时使用的方法……很久以前！=P
This is what I used when I wanted to do something like that... a long time ago! =P
$sql = "SELECT image FROM table WHERE cond ORDER BY xxxx DESC LIMIT 5";
$result = mysqli_query($db,$sql);
while($arraySomething = mysqli_fetch_array($result))
{
echo "<img src='php/imgView.php?imgId=".$arraySomething."' />";
}
这篇关于如何显示存储在 MySql 数据库中的 BLOB 图像?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
