来自多个表的MYSQL左连接计数 [英] MYSQL Left Join COUNTS from multiple tables

查看:62
本文介绍了来自多个表的MYSQL左连接计数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想添加表示来自其他表的计数的列.

I want to add columns that represent counts from other tables.

我有 3 张桌子.

消息

MessageID    User      Message      Topic
1            Tom       Hi           ball
2            John      Hey          book
3            Mike      Sup          book
4            Mike      Ok           book

主题

Topic      Title     Category1    Category2
ball       Sports    Action       Hot
book       School    Study        Hot

Stars_Given

starID     Topic
1          ball
2          book
3          book
4          book

我想结束:

Topic_Review

Topic    Title     StarCount    UserCount    MessageCount
ball     Sports    1            1            1
book     school    3            2            3

所以基本上我想附加 3 列,其中包含唯一值的计数(每个主题中给出的星数、在主题中拥有消息的唯一用户以及每个主题中唯一消息的数量).

So basically I want to attach 3 columns with counts of unique values (number of stars given within each topic, unique users who have messages within topic, and the number of unique messages in each topic).

我希望最终也能够过滤类别(查看两列).

I want to eventually be able to filter on the categories (look in both columns) as well.

此外,我想最终按我加入的计数进行排序.例如,我将有一个按钮,按升序按星数"排序,或按降序按用户数"排序,等等.

Also, I want to eventually sort by the counts that I join. Example, I'm going to have a button that sorts by "number of stars" by ascending order, or sort by "number of users" by descending order, etc.

我尝试调整其他人的答案,但无法正常工作.

I've tried adapting other people's answers and I can't get it to work properly.

推荐答案

select
  t.Topic,
  t.Title,
  count(distinct s.starID) as StarCount,
  count(distinct m.User) as UserCount,
  count(distinct m.messageID) as MessageCount
from
  Topics t
  left join Messages m ON m.Topic = t.Topic
  left join Stars_Given s ON s.Topic = t.Topic
group by
  t.Topic,
  t.Title

Sql Fiddle

或者,您可以在子查询中执行聚合,如果表中有大量数据,这可能会更有效:

Sql Fiddle

Or, you can perform the aggregation in sub-queries, which will likely be more efficient if you have a substantial amount of data in the tables:

select
  t.Topic,
  t.Title,
  s.StarCount,
  m.UserCount,
  m.MessageCount
from
  Topics t
  left join (
    select 
      Topic, 
      count(distinct User) as UserCount,
      count(*) as MessageCount
    from Messages
    group by Topic
  ) m ON m.Topic = t.Topic
  left join (
    select
      Topic, 
      count(*) as StarCount
    from Stars_Given 
    group by Topic
  ) s ON s.Topic = t.Topic

这篇关于来自多个表的MYSQL左连接计数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆