使用 MAX 和 GROUP BY 选择所有相应的字段 [英] Selecting all corresponding fields using MAX and GROUP BY

问题描述

我有这张桌子:

我想发出一个请求，该请求将为每个 deal_id 返回具有最高 timestamp、 和相应 status_id.

And I would like to make a request that would return for each deal_id the row with the highest timestamp, and the corresponding status_id.

所以对于这个例子，我会返回 2 行:

So for this example, I would have returned 2 rows :

1226, 3, 2009-08-18 12:10:25
1227, 2, 2009-08-17 14:31:25

我试着用这个查询来做

SELECT deal_id, status_id, max(timestamp) FROM deal_status GROUP BY deal_id

但它会返回错误的status_id :

1226, 1, 2009-08-18 12:10:25
1227, 1, 2009-08-17 14:31:25

推荐答案

如果没有一个主键字段，我认为最好的选择是:

without a single primary key field, I think your best bet is:

select * from deal_status
inner join
  (select deal_id as did, max(timestamp) as ts
  from deal_status group by deal_id) as ds
  on deal_status.deal_id = ds.did and deal_status.timestamp = ds.ts

如果您允许同一产品同时具有两种不同的状态，这仍然不起作用

this still won't work if you allow having two different statuses for the same product at the same time

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