Swagger 没有为 IActionResult 包装的对象生成模型 [英] Swagger not generating model for object wrapped by IActionResult

问题描述

使用以下代码，Swaggger UI 显示 RegistrationInfo 模型，但不显示 UserInfo 模型.

With the following code, Swaggger UI shows the RegistrationInfo model but not the UserInfo model.

我如何让它生成?

[Produces("application/json")]
[Authorize(AuthenticationSchemes = JwtBearerDefaults.AuthenticationScheme)]
[Route("api")]

public class UserController : Controller
{

    [HttpPost("RegisterUser")]
    public  IActionResult RegisterUser([FromBody] RegistrationInfo info)
    {
        UserInfo data =    UserData.RegisterUser(info);
        if (data != null)
        {
            return Ok(data);
        }
        return NoContent();
    }
}

推荐答案

您需要使用 ProducesResponseType 属性.将您的控制器更改为:

You need to use the ProducesResponseType attribute. Change your controller to this:

[Produces("application/json")]
[Authorize(AuthenticationSchemes = JwtBearerDefaults.AuthenticationScheme)]
[Route("api")]
public class UserController : Controller
{
    [ProducesResponseType(typeof(UserInfo), StatusCodes.Status200OK)]
    [HttpPost("RegisterUser")]
    public IActionResult RegisterUser([FromBody] RegistrationInfo info)
    {
        UserInfo data = UserData.RegisterUser(info);
        if (data != null)
        {
            return Ok(data);
        }

        return NoContent();
    }
}

查看更多这里.

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