指定散点图中每个点的颜色(matplotlib) [英] Specify color of each point in scatter plot (matplotlib)

问题描述

我有一个使用 matplotlib 创建的 3D 图，我有一个对应于每个点的 rbg 值列表.

I have a 3D Plot that I created using matplotlib, and I have a list of rbg values that correspond to each point.

我有 X、Y 和 Z 数据，然后我有表单的颜色列表":

I have the X, Y, and Z data, and then I have a "color list" of the form:

[ (r,g,b), (r,g,b), ... , (r,g,b) ]

匹配每个 (x, y, z) 点.

to match each (x, y, z) point.

现在，我有

fig = plt.figure()
ax = fig.add_subplot(111, projection = '3d')

ax.scatter(X, Y, Z)
plt.show()

合并这些 rgb 元组以便为每个点分配特定颜色的合适方法是什么?

What's the appropriate way to incorporate those rgb tuples so that each point will be assigned a specific color?

推荐答案

我使用 for 循环将每种颜色单独分配给每个点.这是我的代码:

I used a for loop to individually assign each color to each point. Here is my code:

X = [1, 2, 3]
Y = [2, 5, 8]
Z = [6, 4, 5]
colors=["#0000FF", "#00FF00", "#FF0066"]

fig = plt.figure()
ax = fig.add_subplot(111, projection = '3d')


for i in range(len(X)):
    ax.scatter(X[i], Y[i], Z[i], color=colors[i])
plt.show()

for 循环逐点进行(因此 [i] 在每个 X、Y、Z 值前面)并一个一个地给出颜色.我在示例中使用了十六进制颜色，但如果您愿意，您也可以使用其他颜色.

The for loop goes point by point (hence the [i] in front of each X,Y,Z value) and gives a color one by one. I used hex colors for my example, but you could probably use something else if you wanted.

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