在 Matlab 中使用 hgtransform 命令绘制 3D 动画图 [英] 3D-Animation plot with the hgtransform command in Matlab

问题描述

我继续考虑 3d 动画(沿曲线移动点)的可能性.我已经编写了以下代码来尝试使用 hgtransform 命令，但我不明白为什么不起作用.

I continue to think of the possibilities for the 3d-animation (moving point along a curve). I have written the following code to try it using the hgtransform command but I do not understand why does not work.

 t = 0:pi/50:10*pi;
    x = sin(t);
    y = cos(t);
    z = t;
    ah = axes;
    set(ah,'XLim',[min(x) max(x)],'YLim',[min(y) max(y)],...
        'ZLim',[min(z) max(z)]);
    plot3(x,y,z,'Color','red');
    hold on;
    view(3);
    hpoint = line('XData',x(1),'YData',y(1),'ZData',z(1),'Color','black','Marker',...
        'o','MarkerSize',10,'MarkerFaceColor','black');
    ht = hgtransform('parent',ah);
    set(hpoint,'Parent',ht);

    for i=2:length(x)
        tx = x(i)-x(i-1);
        ty = y(i)-y(i-1);
        tz = z(i)-z(i-1);
        trans = makehgtform('translate',[tx ty tz]),      
        set(ht,'Matrix',trans);
        pause(0.01);
    end

推荐答案

你必须计算 tx、ty 和 tz 在你的循环如下:

You have to calculate tx, ty, and tz in your loop as follows:

tx = x(i)-x(1);  %# Note the 1 instead of i-1
ty = y(i)-y(1);
tz = z(i)-z(1);

这是因为您应用到该点的变换 trans 是一个 绝对 变换.换句话说，变换应用于每次循环迭代中点的原始位置，而不是最近位置.

This is because the transform trans that you apply to the point is an absolute transform. In other words, the transform is applied to the original position of the point on each loop iteration, not to the most recent position.

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