四元数和球面旋转坐标之间的正确转换? [英] Proper conversion between Quaternions and Spherical Rotation Coordinates?
问题描述
我正在了解更多四元数转换,但我对本网站以下部分的四元数到球面旋转转换代码有疑问:
I'm learning about more quaternion conversions and I have a question regarding quaternion to spherical rotation conversion code at the following section of this website:
http:///web.archive.org/web/20041029003853/http://www.j3d.org/matrix_faq/matrfaq_latest.html#Q59
这段代码中的angle和sin_angle应该是什么?从未使用过角度,所以我猜是旋转角度.sin_angle 应该是 sin_a 吗?
What are angle and sin_angle in this code supposed to be? Angle is never used so I was guessing it's the rotation angle. Is sin_angle supposed to be sin_a?
如果这是一个返回带有球面旋转数据的浮点数组的函数,那么 [angle, latitude, longitude] 是否是转换后的四元数的合适表示?
If this was a function returning an array of float with the spherical rotation data, would [angle, latitude, longitude] be an appropriate representation of the converted quaternion?
cos_a = W;
sin_a = sqrt( 1.0 - cos_a * cos_a );
angle = acos( cos_a ) * 2;
if ( fabs( sin_angle ) < 0.0005 ) sin_a = 1;
tx = X / sin_a;
ty = Y / sin_a;
tz = Z / sin_a;
latitude = -asin( ty );
if ( tx * tx + tz * tz < 0.0005 )
longitude = 0;
else
longitude = atan2( tx, tz );
if ( longitude < 0 )
longitude += 360.0;
推荐答案
四元数是四个数字 [X,Y,Z,W]
编码旋转方向和角度.该代码提取此信息并将旋转轴转换为纬度和经度.
A quaternion is four numbers [X,Y,Z,W]
that encode a rotation direction and an angle. The code extracts this information and converts the rotation axis into a latitude and longitude.
- 从旋转轴
[tx,ty,tz]
和角度theta
构造四元数是X = tx*SIN(theta/2)
Y = ty*SIN(theta/2)
Z = tz*SIN(theta/2)
W = COS(theta/2)
- Quaternion construction from rotation axis
[tx,ty,tz]
and angletheta
isX = tx*SIN(theta/2)
Y = ty*SIN(theta/2)
Z = tz*SIN(theta/2)
W = COS(theta/2)
这段代码正好相反,因为
angle = 2*ACOS(W) = 2*(theta/2) = theta
.所以变量angle
存储旋转角度.This code does the reverse, since
angle = 2*ACOS(W) = 2*(theta/2) = theta
. So the variableangle
stores the rotation angle.这篇关于四元数和球面旋转坐标之间的正确转换?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!